Answer:
B => Mg° => Mg⁺² + 2e⁻
Explanation:
2Mg° + O₂ => 2MgO rewrite => Mg° + 1/2O₂ => 2MgO
Oxidation Half Rxn => Mg° => Mg⁺² + 2e⁻
Reduction Half Rxn => 1/2O₂ + 2e⁻ => 2O⁻
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FYI Note => For half-reactions one always finds the electrons listed on the product side of the reaction for oxidation reactions and for reduction reactions on the reactant side.
B.Prism because it’s triangular and a cylinder is circular
Answer:
It going to be confusing to see 10 skyscrapers that look the same and hard to go to the right one
Explanation:
Barium forms cation : Ba²⁺
<h3>Further explanation</h3>
Given
Barium element
Required
Ion type
Solution
Barium with the symbol Ba is an alkaline earth metal element having the atomic number 56
Electron configuration of Barium: [Xe] 6s2
If we look at this configuration, then Barium will try to achieve stability by removing 2 electrons so that the electron configuration is the same as the noble gas Xenon (Xe)
Because it removes 2 electrons, Barium has the number of protons> the number of electrons so that the charge is positive and forms a cation
Answer: The number 4 indicates 4 electrons.
Explanation: We are given an electronic configuration, which is:
Here,
- The letters denote the sub-shells of an element.
- The numbers written before the letters which are 1, 2 and 2 represents the Principle Quantum Number and these represents the energy level of the sub-shells.
- The number which are written in the superscripts which are 2, 2 and 4 denotes the electrons which are present in the sub-shell.
Hence, 4 indicates 4 electrons present in 2p sub-shell.
