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Anna [14]
3 years ago
12

What is the frequency of a photon with a wavelength of 1040 nm. Report your answers to three significant digits. The frequency i

s = _________ s-1
Chemistry
1 answer:
Sav [38]3 years ago
6 0

Answer:

Frequency=2.88\times 10^{14}\ s^{-1}

Explanation:

The relation between frequency and wavelength is shown below as:

c=frequency\times Wavelength


c is the speed of light having value 3\times 10^8\ m/s

Given, Wavelength = 1040 nm

Also, 1 m = 10^{-9} nm

So,  

Wavelength = 1040\times 10^{-9} m

Thus, Frequency is:

Frequency=\frac{c}{Wavelength}

Frequency=\frac{3\times 10^8}{1040\times 10^{-9}}\ s^{-1}

Frequency=2.88\times 10^{14}\ s^{-1}

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Filtration is used to separate large particles but this process does not provide pure solutions as some impurities still remain in the solution. On the other hand, distillation helps in the formation of pure water as it removes the impurities from the water or solution.

7 0
3 years ago
You are instructed to create 900. mL of a 0.29 M phosphate buffer with a pH of 7.8. You have phosphoric acid and the sodium salt
Aleksandr [31]

Answer:

B and C

Explanation:

When we have to do a buffer solution we always have to choose the reaction that has the <u>pKa closer to the desired pH value</u>. When we find the pKa values we will obtain:

pKa_1=-Log[6.9x10^-^3]=2.16

pKa_2=-Log[6.2x10^-^8]=7.20

pKa_3=-Log[4.8x10^-^13]=12.31

The closer value is pKa2 with a value of 7.2. Therefore we have to use the second reaction. In which  H_2PO_4^-^1 is the <u>acid</u> and HPO_4^-^2 is the <u>base</u>. Therefore the answer for the first question is B and the answer for the second question is C.

8 0
3 years ago
Pick the correct statement for the following isotope: a. 42Ca 42 is the mass number and 20 is the atomic number. b. 42 is the nu
kramer

Answer:

A

Explanation:

To label an element correctly using a combination of the symbol, mass number and atomic number furnishes some important information about the element.

We can obtain these information from the element provided that correct labeling of the element is presented. Firstly, after writing the symbol of the element, the atomic number is placed as a subscript on the left while the mass number of the atomic mass is placed as a superscript on the same left.

Looking at the question asked, we have the element symbol in the correct position as Ca, with 42 also in the correct position which is the mass number. The third number which is 20 is thus the atomic number of the element.

4 0
3 years ago
Why did Rutherford choose alpha particles in his experiment?
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Rutherford used gold for his scattering experiment because gold is the most malleable metal and he wanted the thinnest layer as possible. The goldsheet used was around 1000 atoms thick. Therefore, Rutherford selected a Gold foil in his alpha scatttering experiment.
5 0
3 years ago
What is the word equation for 2Mg+O2=2 MgO
yarga [219]

Answer:

magnesium + oxygen ----> magnesium oxide

8 0
3 years ago
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