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FrozenT [24]
3 years ago
14

Which statement best explains why the overall charge on an atom is zero?

Physics
2 answers:
garri49 [273]3 years ago
8 0

Answer:

idk what the statements are.... but I think I have an idea of what you're looking for...

~~~~The positive charge of protons in the nucleus equals the negative charge in the electron cloud ~~~~

Alexandra [31]3 years ago
8 0

Answer:

B. The positive charge of the protons in the nucleus equals the negative charge in the electron cloud.

Explanation:

u>u don't question u>u

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fgiga [73]
Human error (average human reaction time is .2 seconds)
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What is a an reason why a object gets extinct
adoni [48]

Answer:

An object may become extinct due to the lack of quantity of the object and the object no longer exists so it is now extinct.

7 0
3 years ago
A certain car battery with a 12.0 V emf has an initial charge of 131 A · h. Assuming that the potential across the terminals sta
irga5000 [103]

Answer:

The battery can supply 130 W for 11.75 h

Explanation:

In order to discover the time in wich the battery can supply this energy we need to find how much current is being drawn from it, we do that by using the equation for real power that is P = V*I, since we have V and P we can solve for I as seen bellow:

I = P/V = 130/12 = 10.834 A

We can use this value to find how many hours the power can supply said current. We do that by dividing the current capacity of the battery by the current drawn:

t = 141/12 = 11.75 h

7 0
3 years ago
A long, thin rod parallel to the y-axis is located at x = - 1 cm and carries a uniform positive charge density λ = 1 nC/m . A se
zheka24 [161]

Answer:

The electric field at origin is 3600 N/C

Solution:

As per the question:

Charge density of rod 1, \lambda = 1\ nC = 1\times 10^{- 9}\ C

Charge density of rod 2, \lambda = - 1\ nC = - 1\times 10^{- 9}\ C

Now,

To calculate the electric field at origin:

We know that the electric field due to a long rod is given by:

\vec{E} = \frac{\lambda }{2\pi \epsilon_{o}{R}

Also,

\vec{E} = \frac{2K\lambda }{R}                  (1)

where

K = electrostatic constant = \frac{1}{4\pi \epsilon_{o} R}

R = Distance

\lambda = linear charge density

Now,

In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.

At x = - 1 cm = - 0.01 m:

Using eqn (1):

\vec{E} = \frac{2\times 9\times 10^{9}\times 1\times 10^{- 9}}{0.01} = 1800\ N/C

\vec{E} = 1800\ N/C     (towards)

Now, at x = 1 cm = 0.01 m :

Using eqn (1):

\vec{E'} = \frac{2\times 9\times 10^{9}\times - 1\times 10^{- 9}}{0.01} = - 1800\ N/C

\vec{E'} = 1800\ N/C     (towards)

Now, the total field at the origin is the sum of both the fields:

\vec{E_{net}} = 1800 + 1800 = 3600\ N/C

7 0
3 years ago
PLEASE HELP ASAP!!! 49 POINTS AND BRAINLIEST FOR BEST AND FASTEST ANSWER!!! (DO NOT ANSWER IF YOU DON'T KNOW, OR I WILL REPORT Y
Colt1911 [192]

Neap tide = tide where there is the least difference between high and low water levels

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Hope this helps!

5 0
3 years ago
Read 2 more answers
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