Love, which can’t be observed or measured directly, is an example of a psychological construct. true or false

A body of mass 1kg has a 25kgsmsqure moment of inertia about its center of mass. if it rotated about an axis which has a displac

ASHA 777 [7]

Answer:

194 kg m²

Explanation:

Use parallel axis theorem:

I = I₀ + mr²

I = 25 kg m² + (1 kg) ((5 m)² + (12 m)²)

I = 25 kg m² + 169 kg m²

I = 194 kg m²

6 0

3 years ago

Determine the potential difference between two charged parallel plates that are 0.50 cm apart and have an electric field strengt

jeka57 [31]

If the field strength between the plates is 9 volts per cm, then over a path of 1/2cm parallel to the field, the potential changes by (1/2) x (9 volts) = 4.5 volts.

5 0

3 years ago

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A. Draw the electric field lines around a negative charge.

Alborosie

<h2>a. Answer:</h2>

We use Electric field lines for visualizing electric fields, so this helps us to see the problem more real. So an electric field line is an imaginary line or curve drawn through a region of space such that the tangent at any point comes from the direction of the electric-field vector at that point. The electric field lines around a negative charge is shown in the First figure below.

<h2>b. Answer:</h2>

Electric forces can be found by using the Coulomb Law's that states <em>that The magnitude of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. </em>This can be expressed as follows:

$F=k\frac{\left | q_{1}q_{2} \right |}{r^2} \\ \\ Where: \\ \\ k=9\times 10^9Nm^2/c^2 \\ \\ q_{1}=0.00150 C \ and \ q_{2}=0.00240 C \\ \\ r=0.900 m$

Then:

$F=9\times 10^9\frac{\left | 0.00150 \times 0.00240 \right |}{(0.900)^2} \\ \\ \therefore \boxed{F=40000N}$

This force is repulsive because the two charges are positive and recall that two positive charges or two negative charges repel each other while a positive charge and a negative charge attract each other.

<h2>C. Answer:</h2>

From the statement, we have two charged objects. Let's say that this charges are:

$q_{1} \ and \ q_{2}$

If the amount of charge on one of the objects is tripled, let's say this is the charge $q_{2}$ , then the new charge is:

$q_{N}=3q_{2}$

In the formula of Coulomb:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2} \\ \\ \therefore F=k\frac{\left | q_{1}(3q_{2}) \right |}{r^2} \\ \\ \therefore \boxed{F=3k\frac{\left | q_{1}q_{2} \right |}{r^2}}$

<em>The conclusion is that if the amount of charge on one of the objects is tripled, the electric force between two charged objects is also tripled</em>

<h2>d. Answer:</h2>

Let's use the Coulomb's Law again to solve this problem. We want to know how the electric force between two charged objects changes if the charges are moved closer together:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2}$

<em>By saying that the charges are moved closer together, we want to express that r becomes smaller. Since r is in the denominator, this implies that the electric force between these two charged objects becomes greater.</em>

<h2>e. Answer:</h2>

From the figure, we can see a metal sphere on a stand. There we have both positive and negative charges. We can say that the positive charge of this sphere is +10q and the negative and the negative charge is -10q. Since the electric charge is conserved, then the algebraic sum of all the electric charges in any closed system is constant. In conclusion, <em>the sphere has no net charge.</em>

<h2>f. Answer:</h2>

Here we want to know how the negative charges in the same sphere are redistributed when a positively charged rod is brought near it. Therefore, positive charge on rod repels positive charges on the sphere, creating zones of negative and positive charge as indicated in the second Figure.

7 0

3 years ago

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Checking Up 1. When a spring scale is used to do work pulling a cart to the top of an incline, where has the energy gone when th

Kobotan [32]

Answer:

1. When a spring scale is used to do work pulling a cart to the top of an incline, the elastic energy stored in the spring is converted into gravitational potential energy, since the top of an incline has a certain height.

2. The roller coaster get its gravitational potential energy from the kinetic energy it carries when it moves with a certain velocity.

3. Truckers use a ramp because it is easier to load a truck with less applied force. Although the work required is the same, without the ramp the force that they should apply is much greater, hence more difficult.

$W = F_1 \times h\\W = F_2 \times d \times \cos(\theta)$

h is greater than (d x cos(Θ)), hence F2 is smaller than F1.

7 0

4 years ago

A block weighing 9.3 N requires a force of 3.7 N to push it along at constant velocity. What is the coefficient of friction for

olga_2 [115]

Answer:

0.398

Explanation:

According to friction, the frictional force is directly proportional to the normal reaction

Ff = nR

Ff is the frictional force

n is the coefficient of friction

R is the reaction

Reaction is equal to the weight

R= W = 9.3N

Fm = Ff = 3.7N

Fm is the moving force

Get the coefficient of friction

n = Ff/R

n = 3.7/9.3

n = 0.398

Hence the coefficient of friction for the surface is 0.398

3 0

3 years ago