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myrzilka [38]
3 years ago
14

a package was determined to have a mass of 5.7kilograms. what's the force of gravity acting on the package on earth?(a)37.93N(b)

1.72N(c)13.44N(d)55.86N
Physics
2 answers:
Nana76 [90]3 years ago
8 0
The force of gravity on earth is 9.807 m/s^2 (or meters per second per second).
To determine the force applied, multiply the mass of the package (5.7 kg) by the force of gravity on Earth (9.807 m/s^2).
5.7 x 9.807 = 55.86 N The answer is D.

Note: the actual force is 55.89 Newtons.
bogdanovich [222]3 years ago
5 0

Answer:

Explanation:

5586

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Answer:

A.Gravity acts to pull the object down

D.The object’s inertia carries it forward.

E.The path of the object is curved.

Explanation:

The motion of a projectile consists of two independent motions:

- A uniform motion along the horizontal direction, with constant horizontal speed

- A vertical motion with constant acceleration of g = 9.8 m/s^2 downward (acceleration due to gravity), due to the presence of the force of gravity, so the vertical velocity changes (increases in the downward direction)

As a result, the combined motion of the projectile has a curved trajectory (parabolic, more specifically). So the following options are correct:

A.Gravity acts to pull the object down --> gravity acts along the vertical direction

D.The object’s inertia carries it forward. --> there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal motion continues with constant speed

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An ocean thermal energy conversion system is being proposed for electric power generation. Such a system is based on the standar
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Answer:

Explanation:

Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.

To objective is to find the:

(i) required heat exchanger area.

(ii) flow rate to be maintained in the evaporator.

Given that:

water temperature = 300 K

At a reasonable depth, the water is cold and its temperature = 280 K

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Q_{supplied } = 66.66 \ MW

However, from the evaporator, the heat transfer Q can be determined by using the formula:

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Also;

\Delta T_1 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_1 = 300 -290 \\ \\ \Delta T_1 = 10 \ K

\Delta T_2 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_2 = 292 -290 \\ \\ \Delta T_2 = 2\ K

LMTD = \dfrac{10 -2}{In (\dfrac{10}{2} )}

LMTD = \dfrac{8}{In (5)}

LMTD = 4.97

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The mass flow rate:

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rusak2 [61]

A small 20-kg canoe is floating downriver at a speed of 2 m/s. 40 J is the canoe’s kinetic energy.

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<u>Explanation:</u>

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