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3 years ago

Which is the correctly balanced chemical equation for the reaction of KOH and H2SO4?

Chemistry

2 answers:

kvv77 [185]3 years ago

6 0

Answer:

2KOH +H2SO4=K2SO4+2H20

Explanation:

Aleks04 [339]3 years ago

4 0

<span>i think the answer should be 2KOH +H2SO4=K2SO4+2H20</span>

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It takes to break an carbon-chlorine single bond. Calculate the maximum wavelength of light for which an carbon-chlorine single

Maslowich

Answer:

It takes approximately $5.43\times 10^{-19}\; \rm J$ of energy to break one $\rm C-Cl$ single bond.

The maximum wavelength of a photon that can break one such bond is approximately $3.66\times 10^{-7}\; \rm m$ (in vacuum.) That's the same as $3.66 \times 10^{2}\; \rm nm$ (rounded to three significant figures.)

Explanation:

<h3>Energy per bond</h3>

The standard bond enthalpy of $\rm C-Cl$ single bonds is approximately $\rm 327\; \rm kJ \cdot mol^{-1}$ (note that the exact value can varies across sources.) In other words, it would take approximately $327\; \rm kJ$ of energy to break one mole of these bonds.

The Avogadro Constant $N_A \approx 6.023\times 10^{23}\; \rm mol^{-1}$ gives the number of $\rm C-Cl$ bonds in one mole of these bonds. Based on these information, calculate the energy of one such bond:

$\begin{aligned}& E(\text{one $\mathrm{C-Cl}$ bond}) \\ &= \frac{E(\text{one mole of $\mathrm{C-Cl}$ bonds})}{N_A} = \frac{327\; \rm kJ\cdot mol^{-1}}{6.023\times 10^{23}\; \rm mol^{-1}} \\ &\approx 5.429\times 10^{-22}\; \rm kJ = 5.429\times 10^{-19}\; \rm J \end{aligned}$ .

Therefore, it would take approximately $5.43\times 10^{-19}\; \rm J$ of energy to break one $\rm C-Cl$ single bond.

<h3>Minimum frequency and maximum wavelength </h3>

The Einstein-Planck Relation relates the frequency $f$ of a photon to its energy $E$ :

$E = h \cdot f$ .

The $h$ here represents the Planck Constant:

$h \approx 6.63 \times 10^{-34}\; \rm J \cdot s$ .

A photon that can break one $\rm C-Cl$ single bond should have more than $5.43\times 10^{-19}\; \rm J$ of energy. Apply the Einstein-Planck Relation to find the frequency of a photon with exactly that much energy:

$\begin{aligned}f &= \frac{E}{h}\\ &\approx \frac{5.43\times 10^{-19}\; \rm J}{6.63 \times 10^{-34}\; \rm J\cdot s} \\ &\approx 8.19 \times 10^{14}\; \rm s^{-1} = 8.19 \times 10^{14}\; \rm Hz\end{aligned}$ .

What would be the wavelength $\lambda$ of a photon with a frequency of approximately $8.19 \times 10^{14}\; \rm Hz$ ? The exact answer to that depends on the medium that this photon is travelling through. To be precise, the exact answer depends on the speed of light in that medium:

$\displaystyle \lambda = \frac{(\text{speed of light})}{f}$ .

In vacuum, the speed of light is $c \approx 2.998\times 10^{8}\; \rm m \cdot s^{-1}$ . Therefore, the wavelength of that $8.19 \times 10^{14}\; \rm Hz$ photon in vacuum would be:

$\begin{aligned} \lambda &= \frac{c}{f} \\ & \approx \frac{2.998\times 10^{8}\; \rm m \cdot s^{-1}}{8.19\times 10^{14}\; \rm s^{-1}} \\ &\approx 3.66 \times 10^{-7}\; \rm m = 3.66 \times 10^{2}\; \rm nm\end{aligned}$ .

(Side note: that wavelength corresponds to a photon in the ultraviolet region of the electromagnetic spectrum.)

7 0

3 years ago

How does thermal energy affect the three states of matter??

Ivenika [448]

An increase in thermal energy, changes the state of matter from solid to liquid to gas.

8 0

4 years ago

2. A 0.45g sample of mineral ore is analyzed for chromium and found to contain

MrRissso [65]

Answer:

Explanation: I don't know

6 0

3 years ago

When baking soda (NaHCO3) dissolves in water, it separates into a cation (positive ion) and an anion (negative ion). Give the ch

goldenfox [79]

Answer:

Na⁺ and HCO⁻₃

Explanation:

When baking soda is dissolve in water it fully ionized into positive and negative ions.

NaHCO₃ + H₂O → Na⁺ + HCO⁻₃

The Na⁺ than react with OH⁻ of water and produced NaOH while HCO⁻₃ react with H⁺ and produce H₂CO₃. This carbonic acid than break to produced carbon dioxide and water.

H₂CO₃ → H₂O + CO₂

Properties of baking soda:

It is odorless compound.

It is solid at room temperature.

It is used in medicine to cure the acidity of stomach.

It is used to make baking powder.

8 0

4 years ago

"No matter what phase water is in, the water molecules stay the same; they just move differently." Explain why this evidence mat

Sedbober [7]

Explanation:

If water is ice-form, only the gap between molecules reduces but the molecule remains the same. The gap between liquid water molecules is greater than that between the molecules. That's why ice is thinner than water.

The intermolecular gap now increases in the gaseous form, which makes it less heavier than solid ice and liquid water. However, the molecule still remain the same.

4 0

3 years ago