Answer:
Total mass of leaked fluorine in six months= 0.405 kg
Explanation:
From the given,
Leaked mass of freon = 35.12 gm
Molecular mass of freon = 
Total weeks per month = 4
Fluorine released into the air in total weeks = 
3 molecules of fluorine is present in the freon
Total mass of fluorine leaked in six months = 
Total mass = x
It would be: x*32.38/100 = 32
x = 3200/32.38 = 97.56
Atomic mass of (OH)2 = 34
So, remaining mass = 97.56-34 = 63.56
which is approximately equal to mass of copper
So, we can say m is copper here, and formula of the compound would be Cu(OH)2
Answer:
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