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poizon [28]
3 years ago
14

How many electrons will metals generally have in their outer shell?

Chemistry
2 answers:
olchik [2.2K]3 years ago
7 0
There is a maximum of two electrons in the outer shell.
Reika [66]3 years ago
3 0

The answer is 8 electrons

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Alkanes do not have geometric isomers because the carbon atoms in their carbon-carbon bonds are _____.
Mariana [72]
The word that best fits the underlined in the sentence is "free-to-rotate." The carbon atoms in their carbon bonds are free to rotate since alkanes do not have geometric isomers. They only have single bonds and the most common example of which are trans molecules. 
6 0
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Ahat [919]
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5 0
4 years ago
HELP!!! TIMED! THANK YOU!
Bess [88]

Answer:

The answer is A.

Explanation:

8 0
3 years ago
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The Haber reaction for the manufacture of ammonia is: N2 + 3H2 → 2NH3 Without doing any experiments, which of the following can
Dimas [21]

Answer :  The correct statement is, \text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

The expression for rate of reaction :

\text{Rate of disappearance of }N_2=-\frac{d[N_2]}{dt}

\text{Rate of disappearance of }H_2=-\frac{1}{3}\frac{d[H_2]}{dt}

\text{Rate of formation of }NH_3=+\frac{1}{2}\frac{d[NH_3]}{dt}

From this we conclude that,

\text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

Hence, the correct statement is, \text{Rate of disappearance of }H_2=3\times (\text{Rate of disappearance of }N_2)

3 0
4 years ago
A dull metal object has a density of 8.8 G/ML and a volume of 20 ML calculate the mass
Alex

Answer:

Mass = 0.000176 gram

Steps:

m =  V × ρ

=  20 milliliter × 8.8 gram/cubic meter

=  2.0E-5 cubic meter × 8.8 gram/cubic meter

=  0.000176 gram

Explanation:

8 0
3 years ago
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