Answer:
Yes, Pb3(PO4)2.
Explanation:
Hello there!
In this case, according to the given balanced chemical reaction, it is possible to use the attached solubility series, it is possible to see that NaNO3 is soluble for the Na^+ and NO3^- ions intercept but insoluble for the Pb^3+ and PO4^2- when intercepting these two. In such a way, we infer that such reaction forms a precipitate of Pb3(PO4)2, lead (II) phosphate.
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The answer is B.
Hope this helps.
To find the net ionic equation we must first write the balanced equation for the reaction. We must bear in mind that the reagents Ca(NO3)2 and Na2S are in the aqueous state and as product we will have CaS in the solid state, since it is not soluble in water and NaNO3 in the aqueous state.
The balanced equation of the reaction will be:
![Ca(NO_3)_{2(aq)}+Na_2S_{(aq)}\rightarrow CaS_{(s)}+2NaNO_{3(aq)}](https://tex.z-dn.net/?f=Ca%28NO_3%29_%7B2%28aq%29%7D%2BNa_2S_%7B%28aq%29%7D%5Crightarrow%20CaS_%7B%28s%29%7D%2B2NaNO_%7B3%28aq%29%7D)
Ca(NO3)2(aq) + → Ca(aq) + 2Na(s)NO3Now, c(aq)ompounds in the aqueous state can be written in their ionic form, so the reaction will transform into:Na2S +
![Ca_{(aq)}^{2+}+2(NO_3)_{(aq)}^-+2Na_{(aq)}^++S_{(aq)}^{2-}\operatorname{\rightarrow}CaS_{(s)}+2Na_{(aq)}^++2NO^-_{3(aq)}](https://tex.z-dn.net/?f=Ca_%7B%28aq%29%7D%5E%7B2%2B%7D%2B2%28NO_3%29_%7B%28aq%29%7D%5E-%2B2Na_%7B%28aq%29%7D%5E%2B%2BS_%7B%28aq%29%7D%5E%7B2-%7D%5Coperatorname%7B%5Crightarrow%7DCaS_%7B%28s%29%7D%2B2Na_%7B%28aq%29%7D%5E%2B%2B2NO%5E-_%7B3%28aq%29%7D)
So, the answer will be option A
Answer:
In the 1H NMR spectrum of ethanol three different signals are observed, this is due to the existence of 3 types of hydrogens with different chemical environment. Hydrogens A (3.57 ppm) are more screened than C (1.10 ppm) due to the presence of oxygen (electonegative atom that removes electron density). The chemical environment of hydrogen B (4.78 ppm), attached directly to oxygen, is also different by resonating at a frequency different from the previous ones.
![C1HC_{3} -C2HA_{2} -OHB](https://tex.z-dn.net/?f=C1HC_%7B3%7D%20-C2HA_%7B2%7D%20-OHB)
The hydroxylic hydrogen produces a singlet, the pair of carbon hydrogens one give rise to a quadruplet and the three hydrogens of carbon two produce a triplet.
Explanation: