<span>In this case we are given a force of 29,000 N. We know
that the equation we can use is:</span>
Force = mass * acceleration
However this is not just any type of force, because this
is the weight of the elevator. So when the force is equal to weight, the
acceleration acting is simply gravity. Therefore:
weight = mass * gravity
Calculating for mass:
mass = 29,000 N / (9.8 m/s^2)
<span>mass = 2,959.18 kg</span>
Answer:
0.2 mm
Explanation:
Assuming the Caliper has 1 mm marks on the main scale. Again, we assume that the 20 division coincides with the 16 main scale division, then we can find the least count by saying
For the given Vernier calipers,
Let one main scale division be = 1 mm.
Since there are 20 Vernier scale divisions that happen to be equal to 16 Main Scale Divisions, we can calculate that
1 Vernier Scale Division = 16/20 Main Scale Division
1 Vernier Scale Division = 0.8 mm.
The least count is finally calculated by saying that
Least Count = 1 Main Scale Division - 1 Vernier Scale Division
Least Count = 1 - 0.8
Least Count = 0.2 mm
Therefore, from the assumptions made above, the least count is 0.2 mm
Every mass is attracted to every other mass with a force that is proportional
to the product of both masses and inversely proportional to the square of the
distance between their centers of mass. The forces act along the line between
their centers of mass.
In my opinion I would say u would electrocute
More, fewer electrons than object is neutral
