Given that number of rabbits on January 1 = 150
We have to find some equation that can be used to find the number of rabbits after x years.
Given that the population of rabbits on a large island doubles every year.
So number of rabbits in 2nd year = 150*2
number of rabbits in 3rd year = 150*2*2=![150(2)^2](https://tex.z-dn.net/?f=%20150%282%29%5E2%20)
number of rabbits in 4th year = 150*2*2*2=![150(2)^3](https://tex.z-dn.net/?f=%20150%282%29%5E3%20)
In same way
number of rabbits in xth year = 150*2*2...=![150(2)^{(x-1)}](https://tex.z-dn.net/?f=%20150%282%29%5E%7B%28x-1%29%7D%20)
In the xth year, population should be 4800
Hence the required equatino is
![4800=150(2)^{(x-1)}](https://tex.z-dn.net/?f=%204800%3D150%282%29%5E%7B%28x-1%29%7D%20)
Question isn't asking for the value of x, so there is no need to solve this equation.
Hence final answer is
.
Answer:
Number of children in each room = c / 3
Step-by-step explanation:
Given:
Number of rooms in care center = 3
Number of children attend the center = c
Find:
Number of children in each room
Computation:
Number of children in each room = Number of children attend the center / Number of rooms in care center
Number of children in each room = c / 3
Answer:
Step-by-step explanation:
Ok
Answer
90ft
Sorry if I’m wrong.