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Verizon [17]
3 years ago
12

Definition: what is a group of protons and neutrons in the center of all atoms.

Physics
2 answers:
Lerok [7]3 years ago
8 0

Atomic Mass Unit or the unit used to measure the masses of subatomic particles. This is the number of protons and neutrons. Area outside the atomic nucleus where the probability of finding electrons is high. This is a group of protons and neutrons in the center of all atoms.

Radda [10]3 years ago
3 0

Explanation:

As it is known that nucleus of an atom consists of protons and neutrons. And, these protons and neutrons are responsible for the mass of an atom.

Hence, the sum of total number of both protons and neutrons is known as atomic mass of an atom.

For example, atomic mass of helium is 4 as it contains 2 protons and 2 neutrons.

On the other hand, only the sum of total number of protons is known as the atomic number of an atom.

For example, atomic number of helium is 2.

Thus, we can conclude that a group of protons and neutrons in the center of all atoms is known as atomic mass.

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Object A of mass 0.70 kg travels horizontally on a frictionless surface at 20 m/s. It collides with object B, which is initially
AnnZ [28]

Answer:

25.71 kgm/s

Explanation:

Let K₁ and K₂ be the initial and final kinetic energies of object A and v₁ and v₂ its initial and final speeds.

Given that K₂ = 0.7K₁

1/2mv₂² = 0.7(1/2mv₁²)

v₂ = √0.7v₁ = √0.7 × 20 m/s = ±16.73 m/s

Since A rebounds, its velocity = -16.73 m/s and its momentum change, p₂ = mΔv = m(v₂ - v₁) = 0.7 kg (-16.73 - 20) m/s = 0.7( -36.73) = -25.71 kgm/s.

Th magnitude of object A's momentum change is thus 25.71 kgm/s

6 0
3 years ago
A metal sample of mass M requires a power input P to just remain molten. When the heater is turned off, the metal solidifies in
vovangra [49]

Answer:

L = Pt/M

Explanation:

Power, P= Q/t = mL/t

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we know that, (Q=m×l)

Now ⇒l= Pt/M

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Thus l= Pt/M

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4 0
3 years ago
A car traveling at 40 ft/sec decelerates at a constant 5 feet per second per second. how many feet does the car travel before co
Tema [17]
<span>This problem is solved by the equation of motion: x = x0 + v0*t + 1/2*a*t^2, Here x0 = 0, v0 = 40ft/sec and a = -5 ft/s^2, we need to solve for t: v = v0 + a*t, solve how long does it take to stop: 0 = v0 + a*t --> a*t = -v0 --> t = -v0/a -- > 40/5 = 8 seconds to stop. In this time, the car travels x = 0 + 40*8 + 0.5*-5*8^2 ft ~ 160 ft. Answer: The car travels 160 ft.</span>
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Answer:

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5 0
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