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My name is Ann [436]
3 years ago
5

Which part of a transverse wave is similar to a compression in a longitudinal wave?

Physics
1 answer:
Sladkaya [172]3 years ago
6 0
In a longitudinal wave, the motion of the medium is parrellel to the direction of the wave.
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A shot-putter accelerates a 7.2 kg shot from rest to 17 m/s . what work did the shot-putter do on the ball?
garri49 [273]
<span>1.0x10^3 Joules The kinetic energy a body has is expressed as the equation E = 0.5 M V^2 where E = Energy M = Mass V = Velocity Since the shot was at rest, the initial energy is 0. Let's calculate the energy that the shot has while in motion E = 0.5 * 7.2 kg * (17 m/s)^2 E = 3.6 kg * 289 m^2/s^2 E = 1040.4 kg*m^2/s^2 E = 1040.4 J So the work performed on the shot was 1040.4 Joules. Rounding the result to 2 significant figures gives 1.0x10^3 Joules</span>
6 0
3 years ago
You illuminate the grating in a spectrometer at normal incidence θi=0° with a beam of light that has a wavelength of 6562.8 Å. T
monitta

Answer:

a) θ₁ = 23.14 ° , b) θ₂ = 51.81 °

Explanation:

An address network is described by the expression

     d sin θ = m λ

Where is the distance between lines, λ is the wavelength and m is the order of the spectrum

The distance between one lines, we can find used a rule of proportions

     d = 1/600

     d = 1.67 10⁻³ mm

    d = 1-67 10⁻³ m

Let's calculate the angle

    sin θ = m λ / d

    θ  = sin⁻¹ (m λ / d)

First order

    θ₁ = sin⁻¹ (1 6.5628 10⁻⁷ / 1.67 10⁻⁶)

    θ₁ = sin⁻¹ (3.93 10⁻¹)

    θ₁ = 23.14 °

Second order

     θ₂ = sin⁻¹ (2 6.5628 10⁻⁷ / 1.67 10⁻⁶)

     θ₂ = sin⁻¹ (0.786)

     θ₂ = 51.81 °

3 0
3 years ago
2. At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (nautical miles per hour; a n
AleksandrR [38]

Answer:

No

Explanation:

Let the reference origin be location of ship B in the beginning. We can then create the equation of motion for ship A and ship B in term of time t (hour):

A = 12 - 12t

B = 9t

Since the 2 ship motions are perpendicular with each other, we can calculate the distance between 2 ships in term of t

d = \sqrt{A^2 + B^2} = \sqrt{(12 - 12t)^2 + (9t)^2}

For the ships to sight each other, distance must be 5 or smaller

d \leq 5

\sqrt{(12 - 12t)^2 + (9t)^2} \leq 5

(12 - 12t)^2 + (9t)^2 \leq 25

144t^2 - 288t + 144 + 81t^2 - 25 \leq 0

225t^2 - 288t + 119 \leq 0

(15t)^2 - (2*15*9.6)t + 9.6^2 + 26.84 \leq 0

(15t^2 - 9.6)^2 + 26.84 \leq 0

Since (15t^2 - 9.6)^2 \geq 0 then

(15t^2 - 9.6)^2 + 26.84 > 0

So our equation has no solution, the answer is no, the 2 ships never sight each other.

8 0
3 years ago
If velocity is positive, which woul
shusha [124]

Answer:

C. An inital volocity that is faster than the final volocity

Explanation:

.

5 0
3 years ago
He power output of a cyclist moving at a constant speed of 5.3 m/s on a level road is 120 w. (a) what is the force exerted on th
EleoNora [17]
P=F*V
F=P/V
F=120/5.3
F=22.6N

8 0
4 years ago
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