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DaniilM [7]
3 years ago
12

Can someone please help me on #17? I don’t get it :(

Chemistry
1 answer:
Dmitry [639]3 years ago
5 0
Given is the specific heat of water equal to 4.18 Joule per gram per *C.

This means to raise the temperature of 1 g of water by 1 degree Celsius we need 4.18 joule of energy.

Now, look at the question. We are asked that how much amount of energy would be required to raise the temperature of 25 g of water by (54-50) = 4 degree celsius.

To do so we have formula

Q = m C (temperature difference)

Have a look at pic for answer

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What is the connection of ascorbic acid when one tablet is dissolved in 200cm cubed of water ?
BartSMP [9]

Answer:

              Option-D: 2.3 × 10⁻³ mol/dm³

Explanation:

Calculate moles of ascorbic acid,

Moles = Mass / M.Mass

Moles = 0.080 g / 176 g/mol

Moles = 0.00045 mole

Also,

Molarity = Moles / Vol. in dm³

Molarity = 0.00045 mol / 0.20 dm³

Molarity = 0.00227 mol.dm⁻¹ or 2.3 × 10⁻³ mol/dm³

5 0
2 years ago
AP chem. Sublevels!!!!!!!!!!!
slavikrds [6]

Answer:

2d

Explanation:

The lowest d is 3d.

Hope this helps!

5 0
2 years ago
14. All the following are necessary parts of a neutralization reaction except A. an indicator. B. a salt. C. water. D. an acid.
ValentinkaMS [17]

The correct answer is <em>B. a Salt </em><em>because The reaction of an acid and a base is called a neutralization reaction because the properties of both the acid and base are diminished or neutralized when they react. A neutralization reaction is a reaction of an acid with a base in aqueous solution to produce water and a salt, as shown by the following equation:</em>

<em>acid + base → salt + water</em>

<em />

<em>* Hopefully this helps:) Mark me the brainliest:) </em>

<em>∞ 234483279c20∞</em>

6 0
3 years ago
How many moles of iron are there in 55.85g of Fe3O4
soldier1979 [14.2K]

Answer:

• Molecular mass of Iron (III) tetraoxide

\dashrightarrow \: { \tt{(56 \times 3) + (16 \times 4)}} \\  = { \tt{168 + 64}} \\  = { \tt{232\:g}}

[ molar masses: Fe → 56, O → 16 ]

\dashrightarrow \:{ \rm{232 \: g \:  = 1 \: mole}} \\ \\   \dashrightarrow \: { \rm{55.85 \: g = ( \frac{55.85}{232}) \: moles }} \\  \\ \dashrightarrow \:  { \boxed{ \tt{ = 0.24 \: moles}}}

8 0
2 years ago
The decomposition of SOCl2 is first-order in SOCl2. If the half-life for the reaction is 4.1 hr, how long would it take for the
qaws [65]
4.1 h = 14760 s 

<span>t 1/2 = ln 2 / k </span>

<span>k = rate reaction = 4.97 x 10^-5 </span>

<span>ln 0.045 / 0.36 = - 4.97 x 10^-5 t </span>

<span>2.08 = 4.97 x 10^-5 t </span>

<span>t = 41839.9 s = 11 h 37 min 19 s</span>
3 0
3 years ago
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