Find the minimum kinetic energy in MeV necessary for an α particle to touch a 39 19 K nucleus that is initially at rest, assumin
g only Coulomb forces are present. Assume that the α particle has a radius of 2.0 fm, and the potassium nucleus of 3.7 fm, and take into account the masses of both particles.
1 answer:
You might be interested in
Answer:
1.8 cm
Explanation:
= mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg
= charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C
=Potential difference through which the ion is accelerated = 215 V
= Speed of the ion
Using conservation of energy
Kinetic energy gained by ion = Electric potential energy lost
= Radius of the path followed by ion
= Magnitude of magnetic field = 0.522 T
the magnetic force on the ion provides the necessary centripetal force, hence
Answer:
Explanation:
The relationship between angle and wavelength for maxima and minima in Young's double slit experiment is given by
For constructive interference
For Destructive interference
where
m=order of maxima and minima
for second order maxima i.e.
For smallest separation taking