As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.
Then friction force = 80 Newtons but in the opposite direction.
Friction force = Mu * Normal force exerted by ground = Mu * weight of box
So we find Mu.
Mu = coefficient of friction between box and horizontal surface
= Force of friction / weight = 80 / 50 * 9.81 = 0.163
When an identical box is placed on top, the force of friction is
= Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons
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A system of millions or billions of stars together with gas and dust, held together by gravitational attraction
Answer:
A) 0.1773
B)Right electrode is the positive one
Explanation:
THIS IS THE COMPLETE QUESTION
certain metal M forms a soluble sulfate salt M S04. Suppose the left half cell of a galvanic cell apparatus is filled with a 4.50 mM solution of M2SO4 and the right half cell with a 4.50 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 20.0 °C. O left Which electrode will be positive? Oright x 5 ? What voltage will the voltmeter show? Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
EXPLANATION;
SEE THE ATTACHMENT BELOW
Answer:
N=mg
g=10-3=7
n=40×7
n=280
Explanation:
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