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alekssr [168]
3 years ago
14

A small cube of metal measures 19.0 mm on a side and weighs 79.6 g. What is the density of the metal in g/cm3?

Physics
1 answer:
Nady [450]3 years ago
8 0

Answer:

density of cube =11.605 g/cm³

Explanation:

density of a substance is the mass per unit volume of that substance.

the density of a substance = \frac{mass}{volume}

volume of a cube = l³,

l = 19.0mm , lets convert mm to cm

1mm = 0.1cm, thus, 19mm =19*0.1 =1.9cm

length of cube =1.9cm

volume of cube = 1.9³

density of cube = \frac{79.6}{1.9^{3} }

density of cube =11.605 g/cm³

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Answer:

It takes 77 N

Explanation:

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A 10 kg mass rests on a table. What acceleration will be generated when a force of 20 N is applied and encounters a frictional f
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Net force acting on mass = 20 - 15 = 5N. ( subtracted cuz friction always opposes the motion i.e it always acts in direction opposite to the motion of the object). According to Newton's 2nd law of motion, F(net) = ma. a =F (net) / m = 5/10 = 0.5 m/s^2. Hope it helps :)
6 0
3 years ago
A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 4.0 m/s, skat
Cerrena [4.2K]

Answer:

a)t=59.817652833125294s \approx 59.8s

b)D_1=894.01m

Explanation:

From the question we are told that

Speed of opposing player V_2=4.0m/s

First player chase his opponent aftert=2.80t

Acceleration of  first player a=0.14 m/s2

Let time of catch be  t_c

a)Generally the Equation for distance covered is mathematically given as follows

Distance to catch First opponent

D_1=\frac{1}{2}(0.14)t^2

D_1=0.07t^2

Distance to covered Second opponent

D_2=(2.8+t)*4

Generally when first opponent catch the second opponent it is represented mathematically as

D_2=D_1

0.07t^2=(2.8+t)*4

0.07t^2=11.2+4t

0.07t^2-4t-11.2

t=59.817652833125294s \approx 59.8s

b)Generally the the total time traveled by the first opponent is mathematically given as

D_1=\frac{t^2}{4}

D_1=\frac{59.8^2}{4}

D_1=894.01m

3 0
3 years ago
Air only has a density of 1.3kg/m². What is the mass of<br>3m^3 of air?​
Katarina [22]

Answer:

m = 3.9 [m³]

Explanation:

We must remember that the density of the substance is defined as the relationship between mass over volume. That is expressed in the following equation:

Ro = m/V

where:

Ro = density = 1.3 [kg/m³]

m = mass [kg]

V = volume = 3 [m³]

Now replacing the values.

m =Ro*V\\m = 1.3*3\\\\m=3.9[m^{3}]

8 0
2 years ago
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