Answer:
a) 6.9*10^14 Hz
b) 9*10^-12 T
Explanation:
From the question, we know that
435 nm is given as the wavelength of the wave, at the same time, we also know that the amplitude of the electric field, E(max) has been given to be 2.7*10^-3 V/m
a)
To find the frequency of the wave, we would be applying this formula
c = fλ, where c = speed of light
f = c/λ
f = 3*10^8 / 435*10^-9
f = 6.90*10^14 Hz
b) again, to find the amplitude of the magnetic field, we would use this relation
E(max) = B(max) * c, magnetic field amplitude, B(max) =
B(max) = E(max)/c
B(max) = 2.7*10^-3 / 3*10^8
B(max) = 9*10^-12 T
c) and lastly,
1T = 1 (V.s/m^2)
