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Tresset [83]
3 years ago
13

Oxygen (O2) is best described as which of the following: An element A compound A mixture

Physics
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

in it's natural state it's an element

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A wrench 0.500 m long is applied to a nut with a force of 80.0 N. Because of the cramped space, the force must be exerted upward
riadik2000 [5.3K]

Answer:

Torque, \tau=34.6\ N.m

Explanation:

It is given that,

Length of the wrench, l = 0.5 m

Force acting on the wrench, F = 80 N

The force is acting upward at an angle of 60.0° with respect to a line from the bolt through the end of the wrench. We need to find the torque is applied to the nut. We know that torque acting on an object is equal to the cross product of force and distance. It is given by :

\tau=Fr\ sin\theta

\tau=80\times 0.5\ sin(60)

\tau=34.6\ N.m

So, the torque is applied to the nut is 34.6 N.m. Hence, this is the required solution.

7 0
3 years ago
A car left point a at 7:30 am and arrived at point b, 162 miles away at 10:30 am. what was its average speed in miles per hour?5
Reika [66]
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3 0
3 years ago
A hockey stick of mass ms and length L is at rest on the ice (which is assumed to be frictionless). A puck with mass mp hits the
krek1111 [17]

Answer:

L = mp*v₀*(ms*D) / (ms + mp)

Explanation:

Given info

ms = mass of the hockey stick

uis = 0 (initial speed of the hockey stick before the collision)

xis = D (initial position of center of mass of the hockey stick before the collision)

mp = mass of the puck

uip = v₀ (initial speed of the puck before the collision)

xip = 0 (initial position of center of mass of the puck before the collision)

If we apply

Ycm = (ms*xis + mp*xip) / (ms + mp)

⇒  Ycm = (ms*D + mp*0) / (ms + mp)

⇒  Ycm = (ms*D) / (ms + mp)

Now, we can apply the equation

L = m*v*R

where m = mp

v = v₀

R = Ycm

then we have

L = mp*v₀*(ms*D) / (ms + mp)

5 0
3 years ago
How do skiers slide across the ice?
Eduardwww [97]
The ice and how the blades are made
7 0
3 years ago
In a few sentences, compare and contrast pressurized water reactors and boiling water reactors.
kondaur [170]
For pressurized water reactors the coolant is not permitted to boil in the core of the PRW, however the coolant in boiling water reactors is permitted to do so in the core of BWR. Pressurized water reactors have an indirect cycle. Whereas, the boiling water reactors go through a direct cycle. Both are light water reactors. 
6 0
3 years ago
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