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Nataliya [291]
3 years ago
14

A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a d

istance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?
Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a distance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?

If the distance from the source is doubled. The amplitude of the magnetic field is smaller 4 times.

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Check all of the following statements that describe velocity.
Nata [24]

Answer:

Choices A, B, and C are correct.

Explanation:

Let us look at each of the choices one by one:

A. It is a vector

Yes. Velocity is a vector, or it's a speed with direction.

B. It is the change in displacement divided by the change in time.

Yes. The velocity can be written as

v = \dfrac{\Delta\bold{x}}{\Delta t}

where \bold{x} is the displacement—a vector quantity.

C. It can be measured in meters per second.

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D. It is the slope of the acceleration vs. time graph.

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4 0
3 years ago
What tools enable people to connect and exchange ideas
aleksklad [387]

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The answer is: "Social Media tools"

Explanation:

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sergij07 [2.7K]

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4 0
2 years ago
A 16 kg mass suspended from a light spring is replaced by a 4 kg mass. What factor changes the frequency of the oscillation? (a)
AnnZ [28]

Answer:

Frequency change by a factor of 2.

(b) is correct option.

Explanation:

Given that,

Mass = 16 kg

Replaced mass = 4 kg

We need to calculate the frequency

Using formula of frequency  

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

Put the value into the formula

f_{1}=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{16}}

f_{1}=\dfrac{1}{2\pi}\dfrac{\sqrt{k}}{4}}....(I)

f_{2}=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{4}}

f_{2}=\dfrac{1}{2\pi}\dfrac{\sqrt{k}}{2}}...(II)

f_{2}=2f_{1}

Hence, Frequency change by a factor of 2.

5 0
3 years ago
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