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Nataliya [291]
3 years ago
14

A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a d

istance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?
Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

A very small source of light that radiates uniformly in all directions produces an electric field with an amplitude of ܧ ௠at a distance R from the source. What is the amplitude of the magnetic field at a point 2R from the source?

If the distance from the source is doubled. The amplitude of the magnetic field is smaller 4 times.

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What happens to the coefficient of friction when the weight is increased? Why is this?
Crazy boy [7]

Answer:

Usually the coefficient of friction remains unchanged

Explanation:

The coefficient of friction should in the majority of cases, remain constant no matter what your normal force is. When you apply a greater normal force, the frictional force increases, and your coefficient of friction stays the same. Here's another way to think about it: because the force of friction is equal to the normal force times the coefficient of friction, friction is increased when normal force is increased.

Plus, the coefficient of friction is a property of the materials being "rubbed", and this property usually does not depend on the normal force.

6 0
3 years ago
Read 2 more answers
Two identical small metal spheres with q1 > 0 and |q1| > |q2| attract each other with a force of magnitude 72.1 mN when se
Brrunno [24]

1) +2.19\mu C

The electrostatic force between two charges is given by

F=k\frac{q_1 q_2}{r^2} (1)

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the charges

When the two spheres are brought in contact with each other, the charge equally redistribute among the two spheres, such that each sphere will have a charge of

\frac{Q}{2}

where Q is the total charge between the two spheres.

So we can actually rewrite the force as

F=k\frac{(\frac{Q}{2})^2}{r^2}

And since we know that

r = 1.41 m (distance between the spheres)

F= 21.63 mN = 0.02163 N

(the sign is positive since the charges repel each other)

We can solve the equation for Q:

Q=2\sqrt{\frac{Fr^2}{k}}=2\sqrt{\frac{(0.02163)(1.41)^2}{8.98755\cdot 10^9}}}=4.37\cdot 10^{-6} C

So, the final charge on the sphere on the right is

\frac{Q}{2}=\frac{4.37\cdot 10^{-6} C}{2}=2.19\cdot 10^{-6}C=+2.19\mu C

2) q_1 = +6.70 \mu C

Now we know the total charge initially on the two spheres. Moreover, at the beginning we know that

F = -72.1 mN = -0.0721 N (we put a negative sign since the force is attractive, which means that the charges have opposite signs)

r = 1.41 m is the separation between the charges

And also,

q_2 = Q-q_1

So we can rewrite eq.(1) as

F=k \frac{q_1 (Q-q_1)}{r^2}

Solving for q1,

Fr^2=k (q_1 Q-q_1^2})\\kq_1^2 -kQ q_1 +Fr^2 = 0

Since Q=4.37\cdot 10^{-6} C, we can substituting all numbers into the equation:

8.98755\cdot 10^9 q_1^2 -3.93\cdot 10^4 q_1 -0.141 = 0

which gives two solutions:

q_1 = 6.70\cdot 10^{-6} C\\q_2 = -2.34\cdot 10^{-6} C

Which correspond to the values of the two charges. Therefore, the initial charge q1 on the first sphere is

q_1 = +6.70 \mu C

8 0
3 years ago
Which of the following choices correctly identifies the process created by moving a magnet through a conducting loop?
jolli1 [7]

Answer: D.) electromagnetic induction

Explanation: Electroctromagnetic induction may be explained as a process whereby electric current is induced or produced by difference in potential resulting from the movement of conductor across a magnetic field.

In simple terms, an electromotive force is induced when a magnet is moved through a conducting loop.

The electromotive force produced by moving a magnet through a conducting loop can be represented by the relation:

E = - N (dΦ / dt)

Where E = electromotive force in voltage

N = number of loop in conductor

dΦ = change in magnetic Flux

dt = change in time

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aleksley [76]

Answer:

the sum of all force being applied to an object.

Explanation:

8 0
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Astar begins as a blank a large cloud of gas and dust
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This is a statement but yes a star forms inside nebulae which are gigantic clouds of gas. stars form inside as the gases own gravity pulls it together after which it becomes large enough to perform fusion and become a star.
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