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Delicious77 [7]
3 years ago
5

Do the same molecules have to be present on both sides of a chemical equation? why or why not?

Physics
1 answer:
Nadusha1986 [10]3 years ago
7 0
Yes, the same molecules have to be present on both sides of a chemical equation. This is because the equation has to be able to be balanced, and without the same amount of each molecule on each side of the equation, it could not be balanced.
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Cual de las escalas de temperatura es la mas antigua
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Answer:

the translation I got for this question is

Which of the temperature scales is the oldest?

Explanation:

and i searched for it and got this=

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Walt ran 5 kilometers in 25 minutes going eastward what is his average velocity
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In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these s
riadik2000 [5.3K]

Answer:

Part a)

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

\alpha = \frac{6(m1 - m_2)g}{3(m_1 + m_2)L + m_{bar}L}

Explanation:

As we know that the see saw bar is massless so here torque due to two masses is given as

\tau = I\alpha

here we will have

\tau = (m_1g - m_2g)(\frac{L}{2})

now we will have inertia of two masses given as

I = (m_1 + m_2)(\frac{L}{2})^2

now we have

I = (m_1 + m_2)\frac{L^2}{4}

now the angular acceleration is given as

\alpha = \frac{\tau}{I}

so we have

\alpha = \frac{2(m_1 - m_2)g}{(m_1 + m_2)L}

Part b)

Now if the rod is not massles then we will have total inertia given as

I = (m_1 + m_2)(\frac{L}{2})^2 + \frac{m_{bar}L^2}{12}

so we will have

I = (m_1 + m_2)\frac{L^2}{4} + \frac{m_{bar}L^2}{12}

now the acceleration is given as

\alpha = \frac{\tau}{I}

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3 years ago
What is a oxidation number
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Oxidation number is the charge.
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