Answer:
30
Explanation:
well I got it right but I'm not sure if it's the same thing
Answer:
Explanation:
This problem indicates that the speed of light in a material medium is 0.5 10⁸ m / s, they ask to find the critical angle between the material and the vacuum
Let's find the refractive index of the material
n = c / v
n = 3 10⁸ / 0.5 10⁸
n = 6
When the material passes from one medium to another, it must comply with the law of refraction
n₁ sin θ = n₂ sin θ₂
for the angle criticize the angles tea2 = 90
tea = sin⁻¹n₂/ n₁
The vacuum replacement index is n₂ = 1
tea = sin⁻¹ (1/6)
tea = 9.59º
Answer:
(a) Height is 4.47 m
(b) Height is 4.37 m
Solution:
As per the question:
Initial velocity of teh ball, 
Angle made by the ramp, 
Distance traveled by the ball on the ramp, d = 5.00 m
Now,
(a) At any point on the projectile before attaining maximum height, the velocity can be given by the eqn-3 of motion:
where
H = 
g = 
= 19.06 m/s
Now, maximum height attained is given by:
Height from the ground = 
(b) now, considering the coefficient of friction bhetween ramp and the ball, 
:
velocity can be given by the eqn-3 of motion:
= 18.7 m/s
Now, maximum height attained is given by:
Height from the ground = 
By putting to much weight on it our body causing it to hurt or fall hope this helps
1. What is the weight of this objects?
Weight is simply the product of mass and gravitational
acceleration. Therefore the weight is:
w = 20 kg * 9.81 m/s^2
w = 196.2 kg m/s^2 = 196.2 N
2. After 5 seconds, how has the object fallen and what is its
speed at this instant?
We can use the formula:
<span>y = v0 t + 0.5 g
t^2</span>
v = v0 + g t
where v0 = 0 since the object starts from rest, y is the
distance it fell, t is time
y = 0 + 0.5 * 9.81 * 5^2 = 122.625 m
<span>v = 0 + 9.81 * 5 = 49.05 m/s</span>
