Answer:
The instantaneous velocity of the rocket the moment before it hits the ground is 50 m/s.
Explanation:
Given;
initial velocity of the rocket, u = 50 m/s
Determine the maximum height reached by the rocket.
at maximum height reached by the rocket, the final velocity, v = 0
v² = u² -2gh
0 = 50² - 2(9.8)h
19.6h = 2500
h = 2500 / 19.6
h = 127.55 m
At maximum height, the time to reach ground is given by;
h = ¹/₂gt²

Before the rocket hits the ground the final velocity will be maximum;
v = u + gt
v = 0 + 9.8 x 5.1
v = 50 m/s
Therefore, the instantaneous velocity of the rocket the moment before it hits the ground is 50 m/s.
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Answer:
The diameter of the hose is 0.326 mm.
Explanation:
Given that,
Speed of car = 28 miles/galllon
We need to calculate the radius
The rate of flow of fluid is from the equation of continuity

Where, A = area of cross sectional

We know that,
The velocity is the ratio of displacement of gas per unit time.


Put the value into the formula



We need to calculate the diameter of the hose

Put the value of r


Hence, The diameter of the hose is 0.326 mm.
The total energy of the system is 88.2 J
Explanation:
The total (mechanical) energy of an object is given by:

where
PE is the potential energy
KE is the kinetic energy
At the starting point, the object is at rest: this means that its kinetic energy is zero, so all its energy is potential energy, which is given by

where
m is the mass of the object
g is the acceleration of gravity
h is the height of the object
In this problem, we have (at point A):
m = 3.0 kg

h = 3.0 m
Substituting, we find:

Learn more about potential energy:
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