Answer:
4m/s2
Explanation:
The following data were obtained from the question:
U (initial velocity) = 10m/s
V (final velocity) = 30m/s
t (time) = 5secs
a (acceleration) =?
Acceleration is the rate of change of velocity with time. It is represented mathematically as:
a = (V - U)/t
Now, with this equation i.e
a = (V - U)/t, we can calculate the acceleration of the race car as follow:
a = (30 - 10)/5
a = 20/5
a = 4m/s2
Therefore, the acceleration of the race car is 4m/s2
The acceleration of the racecar is:
83.33% of the roof area will be occupied by the PV cells
Given the data in the question;
time-averaged lighting requirement = 10 W/m²
the annual average solar irradiance = 150 W/m²
the PV efficiency η = 10% = 0.1
battery charging/discharging efficiency η = 80% = 0.8
we know that; Annual average power to the light = × A
Now, the electrical power delivered by the solar cell battery system will be;
⇒ × A × η × η
A = × A × η × η
Such that;
A = A / × A × η × η
A / A = / × η × η
so we substitute
A / A = 10 W/m² / [ 150 W/m² × 0.1 × 0.8 ]
A / A = 10 W/m² / 12 W/m²
A / A = 0.8333
A / A = (0.8333 × 100)%
A / A = 83.33%
Therefore, 83.33% of the roof area will be occupied by the PV cells.
i think it is B