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Vlad1618 [11]
4 years ago
6

A racecar driver on a flat racetrack steps on the gas, changing her velocity from 10 m/sec to 30 m/sec in 5 seconds. What is the

acceleration of the racecar during that time frame?
Physics
2 answers:
erastova [34]4 years ago
8 0

Answer:

4m/s2

Explanation:

The following data were obtained from the question:

U (initial velocity) = 10m/s

V (final velocity) = 30m/s

t (time) = 5secs

a (acceleration) =?

Acceleration is the rate of change of velocity with time. It is represented mathematically as:

a = (V - U)/t

Now, with this equation i.e

a = (V - U)/t, we can calculate the acceleration of the race car as follow:

a = (V - U)/t

a = (30 - 10)/5

a = 20/5

a = 4m/s2

Therefore, the acceleration of the race car is 4m/s2

VLD [36.1K]4 years ago
8 0

Answer:

a = 4\,\frac{m}{s^{2}}

Explanation:

The acceleration of the racecar is:

a = \frac{v-v_{o}}{\Delta t}

a = \frac{30\,\frac{m}{s} - 10\,\frac{m}{s} }{5\,s}

a = 4\,\frac{m}{s^{2}}

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A model rocket is launched straight upward from the surface of the Earth at a speed of 50 m/s. If air resistance is negligible,
romanna [79]

Answer:

The instantaneous velocity of the rocket the moment before it hits the ground is 50 m/s.

Explanation:

Given;

initial velocity of the rocket, u = 50 m/s

Determine the maximum height reached by the rocket.

at maximum height reached by the rocket, the final velocity, v = 0

v² = u² -2gh

0 = 50² - 2(9.8)h

19.6h = 2500

h = 2500 / 19.6

h = 127.55 m

At maximum height, the time to reach ground is given by;

h = ¹/₂gt²

t = \sqrt{\frac{2h}{g} } \\\\t =  \sqrt{\frac{2*127.55}{9.8} }\\\\ t = 5.1 \ s

Before the rocket hits the ground the final velocity will be maximum;

v = u + gt

v = 0 + 9.8 x 5.1

v = 50 m/s

Therefore, the instantaneous velocity of the rocket the moment before it hits the ground is 50 m/s.

3 0
4 years ago
A softball with a mass of 0.11 kg goes moves at a speed of 12 m/s, then the ball is hit by a bat and rebounds in the opposite di
dimulka [17.4K]
=1244 and that's from my math book
7 0
3 years ago
I NEED HELP VERY SOON PLEASE
Igoryamba
I would say d  if i was you 

 
7 0
3 years ago
You're in a car that gets 28 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and
Nataly [62]

Answer:

The diameter of the hose is 0.326 mm.

Explanation:

Given that,

Speed of car = 28 miles/galllon

We need to calculate the radius

The rate of flow of fluid is from the equation of continuity

\dfrac{V}{t}=Av

Where, A = area of cross sectional

\dfrac{V}{t}=\pi r^2v

We know that,

The velocity is the ratio of displacement of gas per unit time.

\dfrac{V}{t}=\pi r^\dfrac{x}{t}

\dfrac{V}{x}=\pi r^2

Put the value into the formula

\dfrac{0.00378541}{28\times1609.34}=\pi r^2

r=\sqrt{\dfrac{0.00378541}{28\times1609.34\times\pi}}

r=1.63\times10^{-4}\ m

We need to calculate the diameter of the hose

d = 2r

Put the value of r

d=2\times1.63\times10^{-4}

d=0.326\ mm

Hence, The diameter of the hose is 0.326 mm.

6 0
3 years ago
If the object starts at point A what is the total energy of the system?
Oxana [17]

The total energy of the system is 88.2 J

Explanation:

The total (mechanical) energy of an object is given by:

E=PE+KE

where

PE is the potential energy

KE is the kinetic energy

At the starting point, the object is at rest: this means that its kinetic energy is zero, so all its energy is potential energy, which is given by

PE=mgh

where

m is the mass of the object

g is the acceleration of gravity

h is the height of the object

In this problem, we have (at point A):

m = 3.0 kg

g=9.8 m/s^2

h = 3.0 m

Substituting, we find:

E=U=(3.0)(9.8)(3.0)=88.2 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

8 0
3 years ago
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