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maria [59]
3 years ago
14

A 0.300 kg ball, moving with a speed of 2.5 m/s, has a head-on collision with at 0.600 kg ball initially at rest. Assuming a per

fectly elastic collision, what will be the velocity of the small ball if the heavier ball has a speed of 2m/s after collision.
Physics
1 answer:
FrozenT [24]3 years ago
4 0

Answer:

1.25 m/s

Explanation:

Given,

Mass of first ball=0.3 kg

Its speed before collision=2.5 m/s

Its speed after collision=2 m/s

Mass of second ball=0.6 kg

Momentum of 1st ball=mass of the ball*velocity

=0.3kg*2.5m/s

=0.75 kg m/s

Momentum of 2nd ball=mass of the ball*velocity

=0.6 kg*velocity of 2nd ball

Since the first ball undergoes head on collision with the second ball,

momentum of first ball=momentum of second ball

0.75 kg m/s=0.6 kg*velocity of 2nd ball

Velocity of 2nd ball=0.75 kg m/s ÷ 0.6 kg

=1.25 m/s

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Lina20 [59]

Explanation:

It is given that,

Force on grindstone, F = 180 N

Radius of grindstone, r = 0.28 m

Mass of grindstone, m = 75 kg

We need to find the angular acceleration of the grindstone. In rotational motion, the relation between the torque and angular acceleration is given by :

\tau=I\times \alpha

\alpha=\dfrac{\tau}{I}

I is the moment of inertia of solid disk, I=\dfrac{1}{2}mr^2

\tau is the torque exerted, \tau=F\times r

\alpha=\dfrac{F\times r}{\dfrac{1}{2}mr^2}

\alpha=\dfrac{2F}{mr}

\alpha=\dfrac{2\times 180\ N}{75\ kg\times 0.28\ m}

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An alpha particle (charge +2e) travels in a circular path of radius .5m in a magnetic field of 1.0 T. Find the (a) period, (b) s
navik [9.2K]

Given Information:

Radius = r = 0.5 m

Magnetic field = 1.0 T

Required Information:

Period = T = ?

Speed = v = ?

Kinetic energy = KE = ?

Answer:

Period = 0.13x10⁻⁶ seconds

speed = 24.16x10⁶ m/s

Kinetic energy = 12.11 MeV

Explanation:

(a) period

The time period of alpha particle is related to its orbital speed as

T = 2πr/v  eq. 1

According to newton's law

F = ma

Force due to magnetic field is given by

F = qvB

qvB = ma

qvB = m(v²/r)

qB = mv/r

v = qBr/m  eq. 2

substitute the eq. 2 in eq. 1

T = 2πr/qBr/m

r cancels out

T = 2π/qB/m

T = 2πm/qB

T = 2π*6.65x10⁻²⁷/2*1.602x10⁻¹⁹*1

T = 0.13x10⁻⁶ seconds

(b) speed

From equation 1

T = 2πr/v

v = 2πr/T

v = 2π*0.5/0.13x10⁻⁶

v = 24.16x10⁶ m/s

(c) kinetic energy (in electron volts)

Kinetic energy is given by

KE = 0.5mv²

KE = 0.5*6.65x10⁻²⁷*(24.16x10⁶)²

KE = 1.94x10⁻¹² J

since 1 electron volt has 1.602x10⁻¹⁹ J

KE = 1.94x10⁻¹²/1.602x10⁻¹⁹

KE = 12.11 MeV

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3 years ago
What quickly forms on a cold glass on a hot day.
Zanzabum
Dew - small water drops, happens all the time, even to windows.
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As a gas or liquid increases in heat, what direction will it naturally move?
miss Akunina [59]

Hello!

Answer:

When a gas gets hot it should go up because of the pressure.

Explanation:

Hope this helps!

3 0
3 years ago
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