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Softa [21]
3 years ago
14

Help me bro, thanks all​

Physics
1 answer:
bagirrra123 [75]3 years ago
3 0
C beautiful yellow silk
D was sleeping
You might be interested in
What would the circuit resistance be if a 7.5 Amp draw was present with the engine running and the charging system producing 15
AlladinOne [14]

Answer:

2 ohms

Explanation:

Hi there!

Ohm's law states that V=IR where V is the voltage, I is the current and R is the resistance.

Plug in the given information (I=7.5, V=15) and solve for R

V=IR\\15=(7.5)R

Divide both sides by 7.5 to isolate R

\frac{15}{7.5}= \frac{7.5R}{7.5}  \\2=R

Therefore, the circuit resistance would be 2 ohms.

I hope this helps!

4 0
3 years ago
Free charges do not remain stationary when close together. To illustrate this, calculate the magnitude of the instantaneous acce
ASHA 777 [7]

Answer:

a=2.304×10¹⁶m/s²

Explanation:

Given data

Distance d=2.5 nm=2,5×10⁻⁹m

Mass of proton m=1.6×10⁻²⁷kg

charge of proton q=1.6×10⁻¹⁹C

To find

acceleration a

Solution

Apply the Coulombs Law

F=k\frac{q_{1}q_{2}  }{r^{2} }

Where k is coulombs constant (k=9×10⁹Nm²/C²)

q=q₁=q₂

r=d

So

F=k\frac{|q^{2} |}{d^{2} }\\ as \\F=ma\\ma=k\frac{|q^{2} |}{d^{2} }\\a=\frac{k}{m} \frac{|q^{2} |}{d^{2} }\\a=\frac{(9*10^{9} )*(1.6*10^{-19} )^{2} }{(1.6*10^{-27} )*(2.5*10^{-9} )^{2} }\\ a=2.304*10^{16}m/s^{2}  

4 0
4 years ago
In a wire with a 1.05 mm2 cross-sectional area, 7.93×1020 electrons flow past any point during 3.97 s. What is the current ????
34kurt

Answer:

The current in the wire is 31.96 A.

Explanation:

The current in the wire can be calculated as follows:

I = \frac{q}{t}

<u>Where</u>:

q: is the electric charge transferred through the surface

t: is the time      

The charge, q, is:

q = n*e

<u>Where</u>:

n: is the number of electrons = 7.93x10²⁰

e: is the electron's charge = 1.6x10⁻¹⁹ C

q = n*e = 7.93 \cdot 10^{20}*1.6 \cdot 10^{-19} C = 126.88 C

Hence, the current in the wire is:

I = \frac{126.88 C}{3.97 s} = 31.96 A

Therefore, the current in the wire is 31.96 A.

I hope it helps you!

3 0
3 years ago
How fast must a 1000 kg car be moving to have a kinetic energy of 2.0*10^3
lawyer [7]
Kinetic Energy is defined by Ke=1/2mv^2. Plug in and solve for v.

2,000 = 1/2(1000)(v)^2
4=(v)^2
v=2 m/s

The car must move at 2 m/s to have a Ke of 2,000 Joules.
6 0
3 years ago
How do the echoes of the sounds of animals help them?
anastassius [24]
Animals like bats and whales use something called echolocation (sounds or echoes that travel to the other animal) these echoes can let one animal let another one know that danger is near or that food is nearby etc it's like a telephone line
7 0
3 years ago
Read 2 more answers
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