Answer:
Acceleration of the car will be 
Explanation:
We have given that car starts from rest so initial velocity of the car u = 0 m/sec
And car traveled 400 m in 10 sec
So distance traveled by car s = 400 m
Time taken to compete this distance t = 10 sec
We have to find the acceleration of the car
From second equation of motion we know that 
So 

So acceleration of the car will be 
Increase as density increase and vise versa.
<span>The wavelength increases when a sound wave travels from a less dense to a more dense medium, the speed increases, and the frequency stays the same.</span>
Answer:
Magnitude the net torque about its axis of rotation is 1.3338 Nm
Explanation:
The radius of the wrapped rope around the drum, r = 1.24 m
Force applied to the right side of the drum, F = 4.56 N
The radius of the rope wrapped around the core, r' = 0.57 m
Force on the cylinder in the downward direction, F' = 7.58 N
Now, the magnitude of the net torque is given by:

where
= Torque due to Force, F
= Torque due to Force, F'

Now,

The net torque comes out to be negative, this shows that rotation of cylinder is in the clockwise direction from its stationary position.
Now, the magnitude of the net torque:

Answer with Explanation:
We know that by Gauss's Law

Where
is permitivity of free space
is the net charge in the hull
Part a)
Applying the given values we get

Part b)
Since the sign of the electric flux is negative we conclude that the electric field lines entering the submarine are more than the electric field lines leaving the submarine. Since negative sign implies that flux by negative charges is dominant.
Answer:
When balloon moves in the downward direction two forces acts on it.
i) Force exerted by air in the upward direction
ii) Weight
According to newton’s second law of motion:
Sum of forces = Ma
W – F = Ma
Mg – F = Ma …….. (i)
when some of the mass m is dropped and balloon is moving in upward direction with acceleration a/2 then,
F – W = (M-m)a/2
F – (M-m)g = (M-m)a/2
F – Mg + mg = Ma/2 – ma/2 ….. (ii)
Adding equation (i) and (ii)
mg = M(3a/2) – ma/2
m(g + a/2) = M(3a/2)
m = M(3a/2)/(g + a/2)