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Citrus2011 [14]
3 years ago
8

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 49.0 cm . The explorer finds that

the pendulum completes 101 full swing cycles in a time of 140 s . What is the value of the acceleration of gravity on this planet?
Express your answer in meters per second per second.
Physics
1 answer:
iren2701 [21]3 years ago
7 0

Answer: g = 10.0 m/s/s

Explanation:

For a simple pendulum, provided that the angle between the lowest and highest point of  his trajectory be small, the oscillation period is given by the following expression:

T = 2π √L/g , where L = pendulum length, g= accelleration of gravity.

We can also define the period, as the time needed to complete a full swing, so from the measured  values, we can conclude the following :

T = 140 sec/ 101 cycles = 1.39 sec

Equating both definitions for T, we can solve for g, as follows:

g = 4 π² L / T² = 4π². 0.49 m / (1.39)² = 10.0 m/s/s

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A 5.0 kg cannonball is fired horizontally at 68 m/s from a 15-m-high cliff. A strong tailwind exerts a constant 12 N horizontal
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Answer:

3.7 m

Explanation:

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t = √ (2h/g) = √(2(15)/9.8) = 1.75 s

Without the tail wind, the ball travels horizontally

d = vt = 68(1.75) = 119 m

The tailwind exerts a constant acceleration on the ball of

a = F/m = 12/5.0 = 2.4 m/s²

The average horizontal velocity during the flight is

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so the distance with tailwind is

d = v(avg)t = 70.1(1.75) = 122.675 m

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2 years ago
What is the difference between the spectrum of an incandescent solid and the spectrum of an incandescent gas?
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Answer:

ncandescent solids emit continuous spectra; incandescent gases emit bright-line spectra.

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Hot gas gases emit a spectrum that depends on the transitions between atomic states, therefore it is a discrete spectrum.

When reviewing the answers, the correct one is:

ncandescent solids emit continuous spectra; incandescent gases emit bright-line spectra.

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∑

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