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Yakvenalex [24]
3 years ago
11

how would the tides on earth be different if the moon revolved around the earth in 15 days instead of 30 days

Physics
1 answer:
loris [4]3 years ago
5 0
 tides would remain the same but neap and spring tide cycle would be cut in half. 
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Projectile's horizontal range on level ground is R=v20sin2θ/g. At what launch angle or angles will the projectile land at half o
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Answer:

\theta = 15^o \: or\: 75^o

Explanation:

As we know that the formula of range is given as

R = \frac{v^2sin2\theta}{g}

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R_{max} = \frac{v^2}{g}

now we need to find such angles for which the range is half the maximum value

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\frac{R}{2} = \frac{v^2}{2g} = \frac{v^2sin(2\theta)}{g}

sin(2\theta) = \frac{1}{2}

2\theta = 30 or 150

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