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3 years ago

Billy drops a ball from a height of 1 m. The ball bounces back to a height of 0.8 m, then

Physics

1 answer:

Andreas93 [3]3 years ago

5 0

Answer:

The displacement is $\Delta H = - 1 \ m$

The distance is $D = 4 \ m$

Explanation:

From the question we are told that

The height from which the ball is dropped is $h = 1 \ m$

The height attained at the first bounce is $h_1 = 0.8 \ m$

The height attained at the second bounce is $h_2 = 0.5 \ m$

The height attained at the third bounce is $h_3 = 0.2 \ m$

Note : When calculating displacement we consider the direction of motion

Generally given that upward is positive the total displacement of the ball is mathematically represented as

$\Delta H = (0 - h ) + ( h_1 - h_1 ) + (h_2 - h_2 )+ (h_3 - h_3)$

Here the 0 show that there was no bounce back to the point where Billy released the ball

$\Delta H = (0 - 1 ) + ( 0.8- 0.8 ) + (0.5 - 0.5 )+ (0.2 - 0.2)$

=> $\Delta H = - 1 \ m$

Generally the distance covered by the ball is mathematically represented as

$D = h + 2h_2 + 2h_3 + 2h_3$

The 2 shows that the ball traveled the height two times

$D = 1 + 2* 0.8 + 2* 0.5 + 2* 0.2$

=> $D = 4 \ m$

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Determine the total moment of inertia of a merry-go round with 5 children sitting on it. Of the five children, four are seated a

BaLLatris [955]

Answer:

Explanation:

Given that,

We have five children.

Each of mass m =30kg

They sit on a merry go round

Mass of Merry go round M= 150kg

Radius of Merry go round is r =2m

Four children sit at the edge of the merry go round but one child sit at the centre.

The four child that sit at the edge are 2m from the centre of the merry go round but the one at the centre is 0m from the centre

Moment of inertia?

Moment of inertia is given as

I=Σmi•ri²

For the question, the moment of inertia is the combination of inertial of child and the merry go round

I= I(merry go round) + I(four child)+ I(last child)

The merry go round is assumed to be a solid cylinder, so it is going to have the moment of inertia of solid cylinder

Then,

I(merry go round ) =½ Mr²

Also, Four of the child has the same moment of inertia, they are 2m form the centre of the merry go round why the last child has no moment of inertia

I= I(merry go round) + I(four child) +I(last child )

I= ½Mr² + 4mr² + mr'²

I = ½ × 150 ×2² + 4×30×2² + 30×0²

I = 300 +480+0

I = 780 kgm²

7 0

3 years ago

A goat enclosure is in the shape of a right triangle. One leg of the enclosure is built against the side of the barn. The other

san4es73 [151]

Answer:

16,18,22

1,3,7

Explanation:

The detailed explanation is contained in the image attached. The lengths are found using Pythagoras theorem and the two lengths reflects the two values of x yielded by the quadratic equation

8 0

3 years ago

A car starts from rest with an acceleration of 5 ft/s. What is its velocity after it has gone 600 ft?

Soloha48 [4]

Answer:

First, let’s correct the question. Acceleration is the rate of change in velocity. Its unit therefore is ft/sec/sec. If S is the distance traveled for a given duration, S = Vot + (1/2)at^2 where Vo is the initial velocity, a is the acceleration and t is the time. For Vo = 0, a = 6m/sec/sec and t = 3 sec. The distance traveled is S = 0 + (1/2) x 6 x 3^2 = 27 meters

3 0

3 years ago

A 5 meter long ladder leans against a wall. The bottom of the ladder slides away from the wall at the constant rate of 1 3 m/s.

Oksana_A [137]

Answer:9.75 m/s

Explanation:

Given

Length of ladder $(L)=5 m$

Foot the ladder is moving away with speed of $\frac{\mathrm{d} x}{\mathrm{d} t}=13 m/s$

From diagram

$x^2+y^2=L^2$ ------1

at $x=3$

$y^2=25-9=16$

$y=4 m$

Now differentiating equation 1 w.r.t time

$2x\frac{\mathrm{d} x}{\mathrm{d} t}+2y\frac{\mathrm{d} y}{\mathrm{d} t}=0$

$x\frac{\mathrm{d} x}{\mathrm{d} t}=-y\frac{\mathrm{d} y}{\mathrm{d} t}$

$3\times 13=-4\times \frac{\mathrm{d} y}{\mathrm{d} t}$

$\frac{\mathrm{d} y}{\mathrm{d} t}=-\frac{3\times 13}{4}=-9.75 m/s$

negative indicates distance is decreasing with time

5 0

3 years ago

If this atom has a balanced charged, how many protons would you expect to find in this atom?

avanturin [10]

The answer would be C because there is six electrons and so there will be six protons because the amount of protons and electrons have to be the same otherwise it would be an unbalanced particle and you wouldn't be able to touch the object it is in without worrying about something happening

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3 years ago

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