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scoundrel [369]
3 years ago
14

Solve the inequality |4x +4| < 12

Mathematics
2 answers:
mel-nik [20]3 years ago
5 0

Start by dividing all terms by 4, to reduce this expression: |x+1| < 3.

Case 1: x+1 is already positive. The abs. val. operator does not change

anything. Then x+1<3, or x<2.

Case 2: (x+1) is negative. The abs. val. operator, in effect, puts a - sign in

front of (x+1): -(x+1)<3. Distributing the - sign: -x - 1 < 3. Adding 1 to both sides: -x < 4. We want to solve for positive x, so we mult. both sides of

-x<4 by -1 AND change the direction of the inequality symbol:

x > -4

Thus, the solution set is (-4,2): All real numbers between -4 and 2.


lana [24]3 years ago
5 0

|4x +4| < 12\\\\ 4|x+1|

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Step 3: Add -bx^2 to both sides.

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adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

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a(dx2+x3−12)

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dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

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a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

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