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lakkis [162]
3 years ago
12

what is the amount of charge that passes through a wire in a given period if time is the rate of electric

Chemistry
2 answers:
Ronch [10]3 years ago
8 0

Electric current

Explanation:

Thepotemich [5.8K]3 years ago
7 0
It is the rate of electric current
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Titration of 0.824 g of potassium hydrogen phthalate required 38.314 g of naoh solution to reach the end point detected by pheno
melamori03 [73]

1.062 mol/kg.

<em>Step 1</em>. Write the balanced equation for the neutralization.

MM = 204.22 40.00

KHC8H4O4 + NaOH → KNaC8H4O4 + H2O

<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)

Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)

= 4.035 mmol KHP

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)

= 4.035 mmol NaOH

<em>Step 4</em>. Calculate the mass of the NaOH

Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)

= 161 mg NaOH

<em>Step 5</em>. Calculate the mass of the water

Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g

= 37.973 g

<em>Step 6</em>. Calculate the molal concentration of the NaOH

<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg

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3 years ago
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2 circles one proton and one nucleon.draw quarks within each. strong nuclear force within protons between quarks and residual strong force between proton and nucleon (up,up,down in proton)

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If an object is not moving its kinetic energy is zero.<br><br> True<br> False
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Answer: This is true because kinetic energy depends on speed. If there's no speed, then there is no kinetic energy.

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Explain how the amount of pressure created by a smaller piston can be the same as the pressure created by a larger piston?
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Pascal's principle : Pressure applied to an enclosed fluid is transmitted undiminished to every part of the fluid, as well as to the walls of the container.

A common application of this is a hydraulic lift used to raise a car off the ground so it can be repaired at a garage. A small force applied to a small-area piston is transformed to a large force at a large-area piston. If a car sits on top of the large piston, it can be lifted by applying a relatively small force to the smaller piston, the ratio of the forces being equal to the ratio of the areas of the pistons.

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I need to know the measurements of this to the appropriate amount of significant figures
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Answer:

[See Below]

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