The answer is b since oxygen has 6 valence electrons.
He discovered this by firing Alpha particles at a gold foil and most alpha particles went through the foil and a few were deflected. The area where the alpha particles were deflected were assumed where the small dense positively charged nucleus was located. And electrons were scattered in the empty space out side the small nucleus.
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The pH of a solution that contains 0.0011 moles of KOH in 393 mL of solution is 2.56. Details about pH can be found below.
<h3>How to calculate pH?</h3>
The pH of a solution can be calculated using the following expression:
pH = - log [H3O+]
However, the hydrogen concentration of the KOH solution can be calculated as follows:
concentration = 0.0011 mol ÷ 0.393 L
concentration = 2.798 × 10-³M
The pH of KOH = - log [2.798 × 10-³M]
pH = 2.56
Therefore, the pH of a solution that contains 0.0011 moles of KOH in 393 mL of solution is 2.56.
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C it is c the answer is c it’s c