Answer: 1ST OPTION A car increases its speed from 5 m/s to 10 m/s
Explanation:IN 1ST OPTION : because the vel and force are in the same direction therefore acceleration is positive
IN 2ND & 3RD OPTION : the force and velocity in opposite direction so its velocity decreases therefore acceleration is negitive
Answer:
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
Explanation:
This scenario can be represented by an arithmetic progression AP.
nth term = a + nd
Where a is the first term given as 2.63 ft.
d is the common difference and is given as 5.3ft.
n is the particular second/time.
To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.
d = nth sum = (n/2)(2a+(n-1)d)
Where n = 10 seconds
a = 2.65 ft
d = 5.3 ft
Substituting the values we have;
d = (10/2)(2×2.65 + (10-1)5.3)
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
This problem is pretty straight forward since we are given
the half time and we simply have to find for the rate constant. The equation
relating the two variable is:
t1/2 = ln(2) / k
where k is the rate constant, therefore:
k = ln(2) / t1/2
k = ln(2) / 14.7 h
<span>k = 0.047 / hour</span>
Explanation:
Formula to calculate the potential at point "a" is as follows.
= 
= -4590 V
Therefore, we can conclude that the potential at point a, which is on the x axis at x = 40.0 cm is -4590 V.
