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likoan [24]
3 years ago
13

You could use newton’s second law to calculate the force applied to an object if you knew the objects mass and its _____.

Physics
1 answer:
olga2289 [7]3 years ago
4 0

Answer:

You could use newton’s second law to calculate the force applied to an object if you knew the objects mass and its <u>acceleration.</u>

Explanation:

By, Newtons second law, the force applied on an object directly varies with the acceleration caused and the mass of the object.

This is given by :

F=m\ a

Where F represents force applied on the object , m represents mass of the object and a represents the acceleration.

In order to calculate force applied on object we require the mass of the object and its acceleration. The force can be calculated by finding the product of mass and acceleration of the object.

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If the third charge (–| q 3 |) is placed at point P, but not held fixed, it will experience a force and accelerate away from the
Mazyrski [523]

Complete Question

The complete question is shown on the first uploaded image

Answer:

A

The potential of this system is  U=6.75*10^{-7}J

B

The electric potential at point p is V_p= -900V

C

The work required is  W= 9*10^{-7}J

D

The speed of the charge is  v=600m/s

Explanation:

A sketch to explain the question is shown on the second uploaded image

Generally the potential energy for a system of two charges is mathematically represented as

            U = \frac{kq_1 q_2}{d}

where k is the electrostatic constant with a value of  k = 9*10^9 N m^2 /C^2

           q is the charge with a value of  q = 1*10^{-9}C

           d is the distance given as   d =5m

Now we are given that  q_1 = q and  q_2 = 3q and

Now substituting values

             U = \frac{9*10^9 *1*10^{-9} * 3*10^{-9}}{5}

                U=6.75*10^{-7}J

The electric potential at point P is mathematically obtained with the formula

             V_p = V_{-q} + V_{-3q}

I.e the potential at q_1 plus the potential at  q_2

Now potential at q_1 is mathematically represented as

                   V_{-q} = \frac{-kq}{s}

and the potential at q_2 is mathematically represented as

                        V_{-3q} = \frac{-3kq}{s}

Now substituting into formula for potential at  P

                  V_p = \frac{-kq}{s} + \frac{-3kq}{s}  = -\frac{4kq}{s}

                       = \frac{4*9*10^9 *1*10^{-9}}{4*10^{-2}}

                      V_p= -900V

The Workdone to bring the third negative charge is mathematically evaluated as

                W =\Delta U = \frac{kq_1q_3}{s} + \frac{kq_2q_3}{s}

                                 = \frac{kq*q}{s} +   \frac{kq*3q}{s}

                                = \frac{4kq^2}{s}

                               = \frac{4* 9*10^9 * (1*10^{-9})^2}{4*10^{-2}}

                              W= 9*10^{-7}J

From the Question are told that the charge q_3 would a force and an acceleration which implies that all its potential energy would be converted to kinetic energy.This can be mathematically  represented as

                   \Delta U = W = \frac{1}{2} m_{q_3} v^2

                         9*10^{-7} = \frac{1}{2} m_{q_3} v^2

Where m_{q_3} = 5.0*10^{-12}kg

Now making v the subject we have

                 v = \sqrt{\frac{9*10^{-12}}{5*10^{-12}*0.5} }

                     v=600m/s  

8 0
3 years ago
What is the value of sin r and sin i in physics​
taurus [48]

Answer:

★The second law of refraction

The ratio of sine of angle of incidence to the sine of angle of refraction is a constant for a light of given colour and for a given pair of media. This law is also called Snell's law of refraction. If 'i' is the angle of incidence and 'r' is the angle of refraction then, Sin i/Sin r = constant

This constant value is called the refractive index of the second medium with respect to the first.

7 0
3 years ago
Protons have a blank change
rewona [7]

Answer:

That is false, Protons have a positive charge, Electrons have a negative charge, and Neutrons have a blank charge.

Explanation:

7 0
3 years ago
Read 2 more answers
A student walks 31 m east, then 16 m west. Make east positive. What is their<br> displacement?
Marianna [84]
Displacement = 31 - 16 = +15 m
3 0
3 years ago
Which statement best describes the relationship between an object's density and its index of refraction? as the optical density
babunello [35]
For future references, the answer is B.
4 0
3 years ago
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