Answer:
B hope help you stay happy
 
        
             
        
        
        
For the first part, use the question M=mol/vol (liters) 
To do this, you have the given 1.6 M solution
divide the 360g by the molar mass of ethanol (44.07) to get moles 
360/44.07=8.16 mol
so 
1.6M = 8.16 mol/x vol
volume: 5.1 Liters
 
        
             
        
        
        
Answer:
Relative humidity is low . 
Explanation:
The wet bulb reads low temperature because due to low humidity of atmosphere , evaporation of water takes place from the wet bulb which makes the bulb cool and therefore it reads lower temperature . In the process of evaporation , heat equal to latent heat of vaporization is taken from the bulb and it loses temperature. 
 
        
             
        
        
        
Answer:
C. 1 cubic foot of loose sand
Explanation:
For many  objects having equal volume , surface area will be maximum 
of the object which has spherical shape . 
But when a sphere is broken into tiny small spheres , total surface area of all the small spheres will be more than surface area of big sphere . 
Hence among the given option , surface area of loose sand will have greatest surface area . Loose sand is equivalent to small spheres . 
 
        
             
        
        
        
Answer:
Explanation:
<u>1) First law of thermodynamic (energy balance)</u>
- Heat released by the the hot water (345K ) = Heat absorbedby the cold water (298 K) + Heat absorbed by the calorimeter
<u>2) Energy change of each substance:</u>
       
Heat released or absorbed = mass × Specific heat × change in temperature
- density of water: you may take 0.997 g/ ml as an average density for the water.
- mass of water: mass = density × volume = 50.0 ml × 0.997 g/ml = 49.9 g
- Specif heat of water: 1 cal / g°C
- Heat released by the hot water:
        Heat₁ = 49.9 g × 1 cal / g°C × (345 K - 317 K) = 49.9 g × 1 cal / g°C × (28K)
- Heat absorbed by the cold water:
        Heat₂ = 49.9 g × 1 cal / g°C × (317 K - 298 K) = 49.9 g × 1 cal / g°C × (19K)
- Heat absorbed by the calorimeter
        Heat₃ = Ccal × (317 K - 298 K) = Ccal × (19K)
<u>4) Balance</u>
49.9 g × 1 cal / g°C × (28 K) = 49.9 g × 1 cal / g°C × (19 K) + Ccal × (19 K)
Ccal = [49.9 g × 1 cal / g°C × (28 K) - 49.9 g × 1 cal / g°C × (19 K) ] / 19K
Ccal = 23.6 cal/ K
- Convert to cal / K to Joule / K
        23.6 cal / K × 4.18 J / cal = 98.6 J/K
Which rounded to 2 signficant figures leads to 99 J/k, which is the first choice.