An astronaut on a distant planet wants to determine its acceleration due to gravity. the astronaut throws a rock straight up wit
h a velocity of +16 m/s and measures a time of 21.2 s before the rock returns to his hand. what is the acceleration (magnitude and direction) due to gravity on this planet? (indicate direction by the sign of the acceleration.)
Define u = 16 m/s, the vertical launch velocity g = acceleration due to gravity, measured positive downward s = vertical distance traveled t = 21.2 s, total time of travel.
The vertical motion obeys the equation s = ut - (1/2)gt²
When the rock is at ground level, s = 0. Therefore (16 m/s)(21.2 s) - 0.5*(g m/s²)*(21.2 s)² = 0 339.2 - 224.72g = 0 g = 1.5094 m/s²
Answer: The acceleration due to gravity is 1.509 m/s² measured positive downward.
They all study under some sect of science. And they all study under different sects of science ie. Biologist study of life Geologists study of Geology, and Physicists study of physics.
