1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fudgin [204]
3 years ago
7

What is newton's 3rd law of physics ​

Physics
1 answer:
ValentinkaMS [17]3 years ago
4 0

Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A.

You might be interested in
1) Calculate the potential energy of a 5.00 kg object sitting on a 3.00 meter high ledge.
maria [59]

Answer:

15kg

Explanation:

5 0
3 years ago
A person's prescription for her new bifocal glasses calls for a refractive power of -0.450 diopters in the distance-vision part,
Angelina_Jolie [31]

Answer:

Far point of the eye is 22.24 m

Far point of the eye is 0.4 m

Explanation:

\frac{1}{f}=-0.045

Object distance = u

Image distance = v

Lens equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=-0.045-\frac{1}{\infty}\\\Rightarrow \frac{1}{v}=\frac{1}{-0.045}\\\Rightarrow v=-22.22\ m

Far point

|v|+\text{Position from eye}\\ =|-22.22|+0.02\\ =22.24\ m

Far point of the eye is 22.24 m

Object distance = u = 0.25-0.02 = 0.23 m

\frac{1}{f}=1.75

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=1.75-\frac{1}{0.23}\\\Rightarrow v=-0.38\ m

Near point

|v|+\text{Position from eye}\\= |-0.38|+0.02\\ =0.4\ m

Far point of the eye is 0.4 m

7 0
3 years ago
HELP
olganol [36]
All the 4 processes are correct answer to change the state of matter. Hope it helps.
8 0
3 years ago
Earth is about 150 million kilometers from the Sun, and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Us
EleoNora [17]

3) Earth is about 150 million km from the Sun, and the apparent brightness of the Sun in our sky is about 1,300 watts per square meter. Determine the apparent brightness we would measure for the Sun if we were located five times Earth's distance from the Sun. Answer: The Sun would appear 1/25 times as bright.
4 0
3 years ago
Read 2 more answers
Why evaporation takes place from the Surface?​
ipn [44]

Answer:

in the water cycle evaporation occurs when the sunlight warms the surface of the water the heat from the sun makes the water molecules move faster and faster until they move so fast they can escape as a gas once evaporated a molecule from water that vapor spends about 10 days in the air

4 0
3 years ago
Other questions:
  • Why were the rings of Uranus not observed directly from telescopes on the ground on Earth? How were they discovered?
    6·1 answer
  • An electric furnace runs 13 hours a day to heat a house during January (31 days). The heating element has a resistance of 7.2 an
    13·2 answers
  • The advantage of a fixed pulley on a flag pole is that it ___________.(1 point)
    14·1 answer
  • Required information Problem 16.048 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS NOTE: This is a multi-part question. Once
    10·1 answer
  • Which of the following changes would cause the fusion rate in the sun’s core to increase?
    10·1 answer
  • The vibrations produced by a jackhammer are used to break up pavement. What type of waves did/does the jackhammer produce into t
    11·1 answer
  • 10. Juan wants to see how air expands when it is heated. He is able to use any of the following supplies - a balloon, a heat lam
    6·2 answers
  • A merry-go-round of radius 2 m is rotating at one revolution every 5 s. A
    12·1 answer
  • An elevator motor provides 45.0 kW of power while lifting an elevator 35.0 m. If the elevator contains seven passengers each wit
    5·1 answer
  • 22. White noise is ...
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!