Please help me out (will give brainliest)

Physics

2 answers:

alisha [4.7K]2 years ago

3 0

Answer:

its black

Explanation:

because thats the color it is

almond37 [142]2 years ago

3 0

Answer:

Constants: 1 atm = 760 mm Hg = 760 torr = 1.01325 bar = 101.325 kPa R = 8.314 J·mol-1K-1= 0.08206 L·atm·mol-1K-11 Calorie = 1 kcal = 4.184 kJ Data:Properties of liquid water: b.p. (at 1 atm) = 100.00°CCH2O(l)= 4.184 J·g-1·K-1ΔHovap= 40.7 kJ·mol-1dH2O(l)(at 25°C) = 1.00 g·mL-1 KfH2O= 1.86 °C·kg·mol-1KbH2O= 0.52 °C·kg·mol-1Po(298 K)= 23.8 mm Hg Properties of ice: m.p. (at 1 atm) = 0.00°CCH2O(s) = 2.06 J·g-1·K-1 dH2O(s)= 0.917 g·mL-1 ΔHofus= 6.02 kJ·mol-1Formulae: ΔGo= ΔHo-TΔSo ΔG = ΔGo+ RT lnQΔGo= -RT lnKeqC = k P (or, S = k P) P = χPoΔT = KmπV = nRT [A]t= -k t + [A]oln[A]t= -k t + ln[A]o1/[A]t= k t + 1/[A]o

I am not sure If that helps im sorry I'm only in middle school :P.

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An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the

poizon [28]

Answer:

The value is $A = 0.014 \ m$

Explanation:

From the question we are told that

The mass of the object is $m = 2.0 \ kg$

The unstressed length of the string is $l = 0.08 \ m$

The length of the spring when it is at equilibrium is $l_e = 5.9 \ cm = 0.059 \ m$

The initial speed (maximum speed)of the spring when given a downward blow $v = 0.30 \ m/s$

Generally the maximum speed of the spring is mathematically represented as

$u = A * w$

Here A is maximum height above the floor (i.e the maximum amplitude)

and $w$ is the angular frequency which is mathematically represented as

$w = \sqrt{\frac{k}{m} }$

$u = A * \sqrt{\frac{k}{m} }$

=> $A = u * \sqrt{\frac{m}{k} }$

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

$b = l -l_e$