<u>Answer:</u> The concentration of KOH solution is 1.215 M
<u>Explanation:</u>
For the given chemical equation:
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Hence, the concentration of KOH solution is 1.215 M
Here we have to get the atom, in the molecule fentanyl, which will behave as a hydrogen (H) bond acceptor from the donor water molecule.
The -O atom in the molecule will behave as the hydrogen bond acceptor from water.
The H-bond always forms between the proton (here water i.e. H₂O) and the proton acceptor atom in a molecule which is essentially is an electronegative element.
In the fentanyl molecule there are two nitrogen (N) atom and one oxygen (O) atom. We know the electronegativity of oxygen is more than the nitrogen. Thus it is expected that the O atom will be H-bond acceptor in the molecule.
The hydrogen bond with water molecule is shown in the figure.
Answer:
solute and solvent
Explanation:
Because solutes dissolves in solvent to form a solution
Answer:
The answer to your question is 1137.45 kJ
Explanation:
Data
mass = 424 g
T1 = 22.6°C
T2 = 149°C
Clw = 4.184 J/g°C
Cv = 2.078 j/g°C
Latent heat = 2257 J/g
Process
1.- Heat of liquid
Heat = (424)(4.184)(100 - 22.6)
Heat = 137308.8 J
2.- Calculate latent heat
Latent heat = (424)(2257)
Latent heat = 956968 J
3.- Heat of vapor
Heat = (424)(2.078)(149 - 100)
Heat = 43172.5 J
4.- Total heat
Heat = 137308.8 + 956968 + 43172.5
Heat = 1137449.3 J = 1137.45 kJ