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3 years ago

If you are given ethanol (C8H18) 6.3lbs/ gal and you have 12 gallons how many moles do you have?

Chemistry

1 answer:

matrenka [14]3 years ago

8 0

Answer:

745.5 moles

Explanation:

Data Given:

Amount of ethanol (C₂H₅OH) = 6.3 lbs/ gal

moles of ethanol (C₂H₅OH) = ?

Solution:

As we have 6.3 lbs per gallon, So, 2 gallons will have total amount of ethanol (C₂H₅OH) will be

Total amount of (C₂H₅OH) will be = 12 x 6.3 lbs

Total amount of (C₂H₅OH) will be = 75.6 lbs

Now,

Convert lb to grams

1 lb = 453.6

75.6 lbs = 75.6 x 453.6 = 34292 g

So, we have 34292 g of ethanol.

Now we have to find number of moles, for which formula will use

no. of moles = mass in grams / molar mass

Molar mass of C₂H₅OH = 2(12) + 5(1) + 16 + 1

Molar mass of C₂H₅OH = 24 + 5 + 16 + 1

Molar mass of C₂H₅OH = 46 g/mol

Put values in the above formula

no. of moles = 34292 g / 46 g/mol

no. of moles = 745.5 moles

no. of moles of ethanol = 745.5 moles

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How do two sublevels of the same principal energy level differ from each other?

dem82 [27]

Two sublevels of the same principal energy level differ from each other through shape and size.

There are mainly 4 energy level s, p, d and f.

The s level has one orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 2.

The p level has three orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 6.

The d level has five orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 10.

The f level has 7 orbital and one orbital have two electrons. So the maximum number of electron in s sublevel is 14.

They may be differ in magnetic level.

Thus, we concluded that Two sublevels of the same principal energy level differ from each other through shape and size.

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1 year ago

Malia was able to make a paperclip float on the surface of water. What will most likely happen to the paperclip if a drop of dis

Arturiano [62]

Answer:

Its A

Explanation:

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3 years ago

A sample of pure NO2 is heated to 335 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+

vodka [1.7K]

The equilibrium constant for the reaction is 0.00662

Explanation:

The balanced chemical equation is :

2NO2(g)⇌2NO(g)+O2(g

At t=t 1-2x ⇔ 2x + x moles

The ideal gas law equation will be used here

PV=nRT

here n= $\frac{w}{W}$ = $\frac{w}{V}$ = density

P = $\frac{density RT}{M}$ density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm

putting the values in reaction

0.75 = $\frac{0.525 x 0.0821 x 608.15 }{M}$

M = 34.61

to calculate the Kc

Kc= $\frac{ [NO] [O2]}{NO2}$

$\frac{1-2x}{1+x}$ x M NO2 + $\frac{2x}{1+x}$ M NO+ $\frac{x}{1+x}$ M O2

Putting the values as molecular weight of NO2, NO,O2

$\frac{46(1-2x) +30(2x)+32x}{1+x}$

34.61= $\frac{46}{1+x}$

x= 0.33

Kc= $\frac{4x^2)x}{1-2x^2}$

putting the values in the above equation

Kc = 0.00662

5 0

2 years ago

Determine the acid dissociation constant for a 0.0250 M weak acid solution that has a pH of 2.37 . The equilibrium equation of i

Oksanka [162]

Answer:

For part (a): pHsol=2.22

Explanation:

I will show you how to solve part (a), so that you can use this example to solve part (b) on your own.

So, you're dealing with formic acid, HCOOH, a weak acid that does not dissociate completely in aqueous solution. This means that an equilibrium will be established between the unionized and ionized forms of the acid.

You can use an ICE table and the initial concentration ofthe acid to determine the concentrations of the conjugate base and of the hydronium ions tha are produced when the acid ionizes

HCOOH(aq]+H2O(l]⇌ HCOO−(aq] + H3O+(aq]

I 0.20 0 0

C (−x) (+x) (+x)

E (0.20−x) x x

You need to use the acid's pKa to determine its acid dissociation constant, Ka, which is equal to

3 0

2 years ago

What is the simplest formula of a compound if a sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z? chemP

Gnoma [55]

Answer:

XY₂Z₄

2.35 mol Z

Explanation:

A sample of the compound contains 0.221 mol X, 0.442 mol Y, and 0.884 mol Z. We can find the simplest formula (empirical formula) by <em>dividing all the numbers of moles by the smallest one</em>.

X: 0.221/0.221 = 1

Y: 0.442/0.221 = 2

Z: 0.884/0.221 = 4

The simplest formula is XY₂Z₄.

The molar ratio of X to Z is 1:4. The moles of Z in a sample that contained 0.588 moles of X is:

0.588 mol X × (4 mol Z/1 mol X) = 2.35 mol Z

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3 years ago

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