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marin [14]
3 years ago
13

How many molecules are in 643.21 grams of Mg3(PO4)2?

Chemistry
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

643.21g  1 mol  6.022^23

262.87 g   1 mol

= 1.4735E24     [Mg3(PO4)2]

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