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3 years ago

Match the change to its definition.

1 answer:

5 0

<h3>Answer:</h3><h3 /><h3>I didnt understand you have already done it perfect </h3>

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2 or more forces that are not equal and opposite of one another can cause change in motion

DedPeter [7]

Answer:

D unbalanced force

Explanation:

i think

4 0

3 years ago

How many moles of oxygen are required to react with 12 moles of FeS2?

Radda [10]

19 moles of O2 probably

3 0

2 years ago

63Ni decays by a first-order process via the emission of a beta particle. The 63Ni isotope has a half-life of 100. years. How lo

rewona [7]

Answer:

151.4863 years

Explanation:

Half life, t1/2 = 100 years

Initial concentration,[A]o = 100%

Final concentration, [A] = 35% (after 65% have been decayed)

Time = ?

Half life for a first Order reaction is given as;

t1/2 = ln (2) / k

k = ln(2) / 100

k = 0.00693y-1

The integral rate law for first order reactions is given as;

ln[A] = ln[A]o − kt

kt = ln[A]o - ln[A]

t = ( ln[A]o - ln[A]) / k

t = [ln(100) - ln(35)] /0.00693

t = 1.0498 / 0.00693

t = 151.4863 years

8 0

3 years ago

If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro

In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.

Molality=

$\frac{Number of moles of solute}{Mass of solvent in kg}$

Number of moles of solute, n=

$\frac{Given mass of the substance}{Molar mass of the substance}$

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,

$n= \frac{0.2 }{123.06}$

Number of moles of nitrobenzene, n= 0.0016 mol

Mass of 10.9 g of naphthalene in kg=0.0109

$Molality= \frac{0.0016}{0.0109 }$

Molality= 0.146 m

7 0

3 years ago

Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution

AlladinOne [14]

Answer:

$V_2=83.3mL$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the volume of the new solution by using the general formula of dilution:

$V_1M_1=V_2M_2$

In such a way, we solve for the final volume, V2, to obtain:

$V_2=\frac{200mL*0.5M}{1.2M}\\\\V_2=83.3mL$

Regards!

3 0

3 years ago