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iren2701 [21]
3 years ago
13

Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . suppose 1

.5 g of hydrochloric acid is mixed with 0.640 g of sodium hydroxide. calculate the maximum mass of water that could be produced by the chemical reaction. be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Aleks04 [339]3 years ago
5 0
The answer is yes I think
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The electron configuration of an element is 1s22s22p¹. How many valence electrons does the element have
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\huge\boxed{\sf 3 \ electrons}

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4 years ago
Read 2 more answers
1. (NH)2CrO-
Alex777 [14]

Question:

1. (NH)2CrO

a) Number of moles of H:

b) Number of moles of N:

Answer:

a) Number of moles of H: 2

b) Number of moles of N: 2

Explanation:

The  (NH)_2CrO is ammonium Chromate which is monoclinic and yellow Crystal that is formed due to the reaction of ammonium Hydroxide and ammonium di-chromate. It is used as catalyst, corrosion inhibitor as well as analytical inhibitors.

Question:

2. Ag.SO.

a) Molar Mass:

b) Percent Composition of Ag:

c) Percent Composition of S:

d) Percent Composition of O:​

Answer:

a) Molar Mass:   155.93 Kg

b) Percent Composition of Ag:   69%

c) Percent Composition of S:  20.5%

d) Percent Composition of O:​ 10.2%

Explanation:

Molar mass =   molar mass of Ag +  molar mass of S +  molar mass of O  

=>107.87+32.06+16

=> 155.93 Kg

Percent Composition of Ag

= \frac{ \text{mass due  to Ag}}{\text {total molar mass}}  \times 100

= \frac{107.87}{155.93} \times 100

= 0.69 \times 100

= 69%

Percent Composition of S:

= \frac{ \text{mass due  to S}}{\text {total molar mass}}  \times 100

=\frac{32.06}{155.93} \times 100

= 0.205 \times 100

= 20.5%

Percent Composition of O:

= \frac{ \text{mass due  to O}}{\text {total molar mass}}  \times 100

= \frac{16.00}{155.93} \times 100

= 0.102 \times 100

= 10.2%

3 0
3 years ago
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