Pb(NO3)2 (aq) + 2 NaI (aq) --> PbI2 (s) + 2 NaNO3 (aq)
Starting with with 200.0 grams of Pb(NO3)2 and 120.0 grams of NaI:
A. What is the limiting reagent?
B. How many grams of PbI2 is theoretically formed?
C. How many grams of the excess reactant remains?
D. If 48 grams of NaNO3 actually formed in the reaction, what is the percent yield of this reaction?
Answer:
17)A. Solids
18) A. Frequently collide with each other and with surface of ballon
19) D. Particles are smaller at lower pressure.
Answer:
The answer to your question is butanal
Explanation:
To name this compound we must consider:
1.- Identify the functional group. The functional group of this molecule is the first carbon to the right and its oxygen.
When carbon is attached to oxygen is a border, this functional group is called Aldehyde.
2.- Count the total number of carbons starting from the right. This molecule has 4 carbons.
3.- Name the compound
An organic molecule with 4 carbons is called butane but change the ending for al, then the name will be butanal