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avanturin [10]
2 years ago
15

Which of the following occurs when a covalent bond forms? Which of the following occurs when a covalent bond forms? Partial char

ges on polar molecules interact. Electrons in valence shells are shared between atoms. Nonpolar molecules are pushed together by surrounding water molecules. Electrons in valence shells are transferred from one atom to another.
Chemistry
1 answer:
Alexus [3.1K]2 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

A covalent bond is defined as the bond which occurs due to sharing of electrons between the combining atoms.

Generally, a covalent bond is formed between non-metals.

For example, both nitrogen and oxygen atoms are non-metals and they combine covalently to form NO_{2} compound.

As nitrogen has 5 valence electrons and an oxygen atom has 6 valence electrons. So, there occurs unequal sharing of electrons between the two.

Thus, we can conclude that when a covalent bond forms then electrons in valence shells are shared between atoms.

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Dmitri Mendeleev's Periodic Law states that chemical and physical properties repeat themselves in groups of _____. A. 4 B. 8 C.
krok68 [10]
<span>Dmitri Mendeleev's Periodic Law states that chemical and physical properties repeat themselves in groups of 8.</span>
6 0
3 years ago
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Gravitational forces exerted on any two____in the universe
OleMash [197]

Answer:-

Gravitational forces exerted on any two <em><u>bodies</u></em> in the universe

Hope it helps you...

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6 0
2 years ago
Please help me as soon as possible! Please help me as soon as possible!
Nastasia [14]

The Answer is D. Suspending a heavy weight with a strong chain.

6 0
3 years ago
1.33 dm3 of water at 70°C are saturated by 2.25
astraxan [27]

Given that 4.50 dm³ of Pb(NO₃)₂ is cooled from 70 °C to 18 °C, the

amount amount of solute that will be deposited is 1,927.413 grams.

<h3>How can the amount of solute deposited be found?</h3>

The volume of water 1.33 dm³ of water 70 °C.

The number of moles of Pb(NO₃)₂ that saturates 1.33 dm³ of water at 70 °C  = 2.25 moles

At 18 °C, the number of moles of Pb(NO₃)₂ that saturates 1.33 dm³ of water = 0.53 moles

Therefore;

Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 70 °C is therefore;

1.33 dm³ contains 2.25 moles.

Number \ of \ moles \ in \ 4.50 \ dm^3 = \dfrac{2.25}{1.33} \times 4.50 \approx \mathbf{7.613 \, moles}

Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 70 °C ≈ 7.613 moles

Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 18 °C is therefore;

1.33 dm³ contains 0.53 moles

Number \ of \ moles \ in \ 4.50 \ dm^3 = \dfrac{0.53}{1.33} \times 4.50 \approx \mathbf{1.79 \, moles}

Number of moles of Pb(NO₃)₂ in 4.50 dm³ at 18 °C ≈ 1.79 moles

The number of moles that precipitate out = The amount of solute deposited

Which gives;

Amount of solute deposited = 7.613 moles - 1.79 moles = 5.823 moles

The molar mass of Pb(NO₃)₂ = 207 g + 2 × (14 g + 3 × 16 g) = 331 g

The molar mass of Pb(NO₃)₂ = 331 g/mol

The amount of solute deposited = Number of moles × Molar mass

Which gives;

The amount of solute deposited = 5.823 moles × 331 g/mol =<u> 1,927.413 g </u>

Learn more about saturated solutions here:

brainly.com/question/2624685

5 0
2 years ago
Draw the structure of the bromohydrin formed when (Z)-3-hexene reacts with Br2/H2O. Use the wedge/hash bond tools to indicate st
Ipatiy [6.2K]

Answer:

(3R,4R)-4-bromohexan-3-ol

Explanation:

In this case, we have  reaction called <u>halohydrin formation</u>. This is a <u>markovnikov reaction</u> with <u>anti configuration</u>. Therefore the halogen in this case "Br" and the "OH" must have <u>different configurations</u>. Additionally, in this molecule both carbons have the <u>same substitution</u>, so the "OH" can go in any carbon.

Finally, in the product we will have <u>chiral carbons</u>, so we have to find the absolute configuration for each carbon. On carbon 3 we will have an "R" configuration on carbon 4 we will have also an "R" configuration. (See figure 1)

I hope it helps!

5 0
3 years ago
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