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vampirchik [111]
3 years ago
11

Write the reaction that occurs when propyl methanoate is hydrolyzed in water and in NaOH

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
5 0

An ester , propyl methanoate ( HCOOC₃H₇) when reacts with sodium hydroxide( NaOH) forms sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH).

The reaction is as follows:

HCOOC₃H₇+NaOH ⇒HCOONa + C₃H₇OH

So when propyl methanoate is hydrolyzed in water and in NaOH then sodium methanoate (HCOONa) as the main product and propanol (C₃H₇OH) forms

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umka21 [38]

Answer:

24.525 g of sulfuric acid.

Explanation:

Hello,

Normality (units of eq/L) is defined as:

N=\frac{eq_{solute}}{V_{solution}}

Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:

eq_{solute}=N*V_{solution}=1\frac{eq}{L}*0.5L=0.5 eq

Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:

m_{H_2SO_4}=0.5eqH_2SO_4(\frac{1molH_2SO_4}{2 eqH_2SO_4}) (\frac{98.1 g H_2SO_4}{1 mol H_2SO_4} )\\m_{H_2SO_4}=24.525 g H_2SO_4

Best regards.

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3 years ago
Question 2: Heat (5 points)
Ronch [10]

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Here, Q is the heat, m is the mass and L is the latent heat of fusion.  

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