A cyclist reduces his speed from 6.5 m/s to 0.0 m/s with an acceleration of
1 answer:
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Answer:
1.1397 Nm
Explanation:
When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth.
If the muscle generates a force
and
, then the torque is equal to
we see that r = 2.65 cm = 0.0265 m
therefore
torque = 0.0265 x 49.5
= 1.1397 Nm
Answer:
Hello your question is incomplete below is the complete question
Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000
answer : V = 1.624* 10^-5 m/s
Explanation:
First we have to calculate the value of a
a = 93 * 10^6 mile/m * 1609.344 m
= 149.668 * 10^8 m
next we will express the distance between the earth and the sun
--------- (1)
a = 149.668 * 10^8
E (eccentricity ) = ( 1/60 )^2
= 90°
input the given values into equation 1 above
r = 149.626 * 10^9 m
next calculate the Earths velocity of approach towards the sun using this equation
------ (2)
Note :
Rc = 149.626 * 10^9 m
equation 2 becomes
(
therefore : V = 1.624* 10^-5 m/s