Answer: 1.3617×10^-14 N
Explanation: The formulae that relates electric field intensity, magnitude of charge and force is given by the formulae below.
F = Eq
Where F = electric force =?
E = strength of electric field = 88000 N/c
q = magnitude of proton charge = 1.602×10^-19 c
By substituting the parameters, we have that
F = 88000 × 1.602×10^-19
F = 13.617×10^-15
F = 1.3617×10^-14 N
Answer:
230.4 N
Explanation:
Applying,
F = kqq'/r²..................... Equation 1
Where F = Electric force, k = Coulomb's constant, q = charge in the ballon, q' = charge in the denium, r = distance between the charges.
From the question,
Given: q = -8.0×10⁻⁶ C, q' = +8.0×10⁻⁶ C, r = 0.05 m
Constant: k = 9×10⁹ Nm²/C²
Substitute these values into equation 1
F = (9×10⁹×8.0×10⁻⁶×8.0×10⁻⁶ )/0.05²
F = (576×10⁻³)/0.0025
F = 230.4 N.
Hey there! A pure substance can be a element.
Hope this helps! :)
Nitrogen gas has a molar mass of about 28.0134 g/mol. Then we have a starting amount of
(42 g) / (28.0134 g/mol) ≈ 1.4993 mol
of N₂.
At standard temperature and pressure, one mole of an ideal gas occupies a volume of about 22.4 L. Then 42 g, or 1.4993 mol, of N₂ takes up
(1.4993 mol) × (22.4 L/mol) ≈ 33.6 L
B. The speed and direction of an object in motion
