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3 years ago

Heyyy! Okay riddle of the day

Physics

1 answer:

vekshin13 years ago

3 0

Answer:

Time to get a new fence...?

C'mon that's pretty cringe lol

Please give brainliest

have a nice day :D

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A 513 g ball strikes a wall at 14.7 m/s and rebounds at 11.3 m/s. The ball is in contact with the wall for 0.038 s. What is the

Natasha_Volkova [10]

consider the velocity of the ball towards the wall as negative and away from the wall as positive.

m = mass of the ball = 513 g = 0.513 kg

v₀ = initial velocity of the ball towards the wall before collision = - 14.7 m/s

v = final velocity of the ball away from the wall after collision = 11.3 m/s

t = time of contact with the wall = 0.038 sec

F = average force acting on the ball

using impulse-change in momentum equation , average force is given as

F = m (v - v₀)/t

inserting the values

F = (0.513) (11.3 - (- 14.7))/0.038

F = 351 N

5 0

3 years ago

The acceleration of an object (in m/s2) is given by the function a ( t ) = 7 sin ( t ) . The initial velocity of the object is v

jok3333 [9.3K]

Answer:

The answer is " $\bold{v(t) = -7 \cos (t) -3}$ "

Explanation:

Consider the function $a(t) = 7 \sin (t)$ speed for an Object , and $V(0) = -10 \frac{m}{s}$ is the initial speed of the object. Find an object-speed v(t) equation:

$\to a(t) = 7 \sin(t) \\\\\to v(t) = \int a(t) dt\\$

$= 7 \int \sin (t) dt \\\\= -7 \cos(t) + C$

Substituting the t = 0 in v(t)

$\to v(0) = - 7 \cos(0) + C \\\\\to -10 = -7(1) +C \\\\\to C = -10 +7\\\\\to C= -3$

after substituting the value C:

$= - 3 in v(t) = -7 \cos (t) +c \\\\\to v(t) = -7 \cos(t) -3$

5 0

3 years ago

Write the equation of a line with a gradient of 5, if y=7 when x=1

alexira [117]

Equation of line is y=mx+c

substitute y and x into y=mx+c,
7=1+c
c=6

hence, y=x+6

7 0

3 years ago

A weight lifter picks up a barbell and

kodGreya [7K]

Answer:

From highest to lowest: $W_1>W_2>W_3$

Explanation:

The work done by a force is given by

$W=Fd cos \theta$

where:

F is the force applied on the object

d is the displacement of the object

$\theta$ is the angle between the direction of the force and of the displacement

In case 1), the barbell is lifted upward. This means that:

- the force applied is upward

- the displacement of the object is upward

This means that $0$ , so the work done is positive: $W_1>0$

In case 2), the barbell is held stationary: this means that the displacement is zero,

$d=0$

And therefore, this means that the work done is also zero:

$W_2=0$

In case 3), the barbell is put down slowly, without dropping it. This means that:

- The force applied is still upward (in fact, the force applied must be upward in order to overcome the force of gravity downward, and avoid the barbell to fall down)

- The displacement of the barbell is downward

This means that $90^{\circ}$ , so $cos \theta$ , and therefore the work done is negative:

$W_3$

So the ranking from greatest to smallest work is

$W_1>W_2>W_3$

8 0

3 years ago

What can be said about all atoms in an element

LenKa [72]

Answer:

All atoms have a dense central core called the atomic nucleus. Forming the nucleus are two kinds of particles: protons, which have a positive electrical charge, and neutrons, which have no charge. All atoms have at least one proton in their core, and the number of protons determines which kind of element an atom is.

Explanation:

6 0

3 years ago