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11. Pete's Pastries sells cupcakes in packs of

1 answer:

jeka943 years ago

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Answer:

102 and 103

Step-by-step explanation:

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Bond [772]

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Part 1) $\frac{a^4}{4b^2}$

Part 2) $-\frac{v^9}{w^6}$

Step-by-step explanation:

we know that

When divide exponents (or powers) with the same base, subtract the exponents

Part 1) we have

$\frac{3a^{2}b^{-4}}{12a^{-2}b^{-2}}=(\frac{3}{12})(a^{2+2})(b^{-4+2} )=\frac{1}{4}a^{4}b^{-2}=\frac{a^4}{4b^2}$

Part 2) we have

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