Answer:
1) t=1.743 sec
2)Vo=61.388 m/sec
3)the x component of its velocity just be- fore it strikes the ground is the same as the initial velocity of the ball that is=61.388 m/sec
4)Vf=17.08 m/s
Explanation:
1)From second equation of motion we get
h=Vit+(1/2)gt^2
here in case(a): Vi=0 m/s,h=14.9m,,put these values in above equation to find the time the ball is in motion
14.9=(0)*t+(1/2)(9.8)t^2
t^2=14.9/4.9
t^2=3.040 sec
t=1.743 sec
2) s=Vo*t
Putting values we get
107=Vo*1.743
Vo=61.388 m/sec
3)the x component of its velocity just be- fore it strikes the ground is the same as the initial velocity of the ball that is=61.388 m/sec
4)From third equation of motion we know that
Vf^2-Vi^2=2gh
here Vi=0 m/s,h=14.9 m
Vf^2=Vi^2+2gh=0+2(9.8)(14.9)
Vf^2=292.04
Vf=17.08 m/s
Answer:
fdvevddvevkejokef0jeovdlvkjeuiyv
Explanation:
ddf4edscd
Answer:
, 
Explanation:
The acceleration of the plane can be determined by means of the kinematic equation that correspond to a Uniformly Accelerated Rectilinear Motion.
(1)
Where 
is the final velocity, 
is the initial velocity, 
is the acceleration and 
is the distance traveled.
Equation (1) can be rewritten in terms of ax:
(2)
Since the plane starts from rest, its initial velocity will be zero (
):
Replacing the values given in equation 2, it is gotten:
So, The acceleration of the plane is 
Now that the acceleration is known, the next equation can be used to find out the time:
(3)
Rewritten equation (3) in terms of t:
<u>Hence, the plane takes 26.92 seconds to reach its take-off speed.</u>
Answer:
charge and distance
Explanation:
The electric force between the two particles are calculated using the formular:
F = kQ₁Q₂ / d²
where:
F = force.
k= Coulomb's law constant.
Q1 and Q2 are the charges.
d= distance.
the equation above is called Coulomb's law.
It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance.
so the correct option is charge and distance.
