Answer:
Explanation:
As we know that tension force in the string will be equal to the centripetal force on the string
so we will have
now we have
now we have
now when string length is 0.896 m and its speed is 71.5 m/s then we will have
A force of 15 N is applied to a spring, causing it to stretch 0. 3 m. What is the spring constant for this particular spring? N/
1 answer:
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Answer:
16.1 m/s
Explanation:
We can solve the problem by using the law of conservation of energy.
At the beginning, the spring is compressed by x = 35 cm = 0.35 m, and it stores an elastic potential energy given by
where k = 316 N/m is the spring constant. Once the block is released, the spring returns to its natural length and all its elastic potential energy is converted into kinetic energy of the block (which starts moving). This kinetic energy is equal to
where m = 0.15 kg is the mass of the block and v is its speed.
Since the energy must be conserved, we can equate the initial elastic energy of the spring to the final kinetic energy of the block, and from the equation we obtain we can find the speed of the block:
D. The new electric potential energy is 1/2as strong as the original
electric potential energy.
