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7nadin3 [17]
3 years ago
12

Taro plants, which are native to Africa, were introduced into Florida's wetland biome in 1910. Today taro plants grow wild in th

e Florida wetlands. African taro plants were able to survive and thrive in Florida because Florida has
A. an environment in which there are no natural consumers of taro plants.
B. a similar ecosystem containing different organisms that play a similar ecological role.
C. a completely different biome that is more suited to taro plant photosynthesis.
D. its own population of the same species of taro plant that were native to Florida
Chemistry
1 answer:
Wewaii [24]3 years ago
6 0
The answer would be b hope it helps
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Which of the following sources of pollution would be the most difficult to track and regulate? a. lawn fertilizer runoff b. a wa
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Which statement about endothermic reactions is true?
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2 years ago
How many grams of CO2 will be produced when 8.50 g of methane react with 15.9 g of O2, according to the following reaction? CH4(
Vedmedyk [2.9K]

Taking into account the reaction stoichiometry, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CH₄ + 2 O₂  → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CH₄: 1 mole
  • O₂: 2 moles
  • CO₂:  1 mole
  • H₂O: 2 moles

The molar mass of the compounds is:

  • CH₄: 16 g/mole
  • O₂: 32 g/mole
  • CO₂:  44 g/mole
  • H₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CH₄: 1 mole ×16 g/mole= 16 grams
  • O₂: 2 moles ×32 g/mole= 64 grams
  • CO₂:  1 mole ×44 g/mole= 44 grams
  • H₂O: 2 moles ×18 g/mole=36 grams

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 16 grams of CH₄ reacts with 64 grams of O₂, 8.50 grams of CH₄ reacts with how much mass of O₂?

mass of O_{2} =\frac{8.50 grams of CH_{4}x64 grams of O_{2} }{16grams of CH_{4}}

mass of O₂= 34 grams

But 34 grams of O₂ are not available, 15.9 grams are available. Since you have less mass than you need to react with 8.50 grams of CH₄, O₂ will be the limiting reagent.

<h3>Mass of CO₂ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 64 grams of O₂ form 44 grams of CO₂, 15.9 grams of O₂ form how much mass of CO₂?

mass of CO_{2} =\frac{15.9 grams of O_{2}x44 grams of CO_{2} }{64grams of O_{2}}

<u><em>mass of CO₂= 10.93 grams</em></u>

Then, 10.93 grams of CO₂ are formed when 8.50 g of methane react with 15.9 g of O₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

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Suppose you had a mixture of sand and small, hollow beads. How might you separate the mixtures ​
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I am not sure if this is the answer but maybe oil?

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