Answer:
3 mol
Explanation:
Given data:
Volume of ethane = 15.0 L
Temperature = 30°C
Pressure = 5.0 atm
Number of moles of ethane = ?
Solution:
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
30+273 = 303 K
5.0 atm × 15.0 L = n×0.0821 atm.L/ mol.K × 303 K
75 atm.L = n× 24.87 atm.L/ mol
n = 75 atm.L / 24.87 atm.L/ mol
n = 3 mol
Extensive property (like volume and mass), can be measured.
Answer:

Explanation:
To convert from moles to grams, the molar mass is used (mass of 1 mole). The values are the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units.
<h3>1. Molar Mass</h3>
We are given the compound sodium hydroxide (NaOH) and we need to look up the molar masses of the individual elements.
- Na: 22.9897693 g/mol
- O: 15.999 g/mol
- H: 1.008 g/mol
The formula for the compound has no subscripts, so there is 1 mole of each element in 1 mole of the substance. We can simply add the molar masses.
- NaOH: 22.9897693 + 15.999 + 1.008 = 39.9967693 g/mol
This means there are 39.9967693 grams of sodium hydroxide in 1 mole.
<h3>2. Convert Grams to Moles </h3>
Use the molar mass we found as a ratio.

Since we are converting 17.6 grams of NaOH to moles, we multiply by this value.

Flip the ratio so the units of grams of NaOH cancel.




<h3>3. Round </h3>
The original measurement of grams has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.
The 0 in the ten thousandths place (in bold above) tells us to leave the 0 in the thousandth place.

17.6 grams of sodium hydroxide are equal to <u>0.440 moles of sodium hydroxide.</u>
Answer:
H2O
H2O
Explanation:
because the are only two hydrogen that can react to Oxygen
Answer is: A. 1.1 3 1023 NiCl2 formula units.
m(NiCl₂) = 24.6 g; mass of nickel(II) chloride.
M(NiCl₂) = 129.6 g/mol; molar mass of nickel(II) chloride.
n(NiCl₂) = m(NiCl₂) ÷ M(NiCl₂).
n(NiCl₂) = 24.6 g ÷ 129.6 g/mol.
n(NiCl₂) = 0.19 mol; amount of nickel(II) chloride.
Na = 6.022·10²³ 1/mol; Avogadro constant.
N(NiCl₂) = n(NiCl₂) · Na.
N(NiCl₂) = 0.19 mol · 6.022·10²³ 1/mol.
N(NiCl₂) = 1.13·10²³; number of formula units.