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DochEvi [55]
3 years ago
13

What conditions must exist for a polyatomic molecule to be nonpolar?

Chemistry
1 answer:
ollegr [7]3 years ago
7 0
  • All atoms in that molecule shall belong to the same element.
  • Otherwise, dipoles must balance each other within the molecule. In such cases, the molecule needs to be symmetric.
<h3>Explanation</h3>

The molecule in question is polyatomic. It contains more than one atoms. That's a rather general definition. Among all non-metals, only the noble gases could form stable monatomic molecules.

Molecules such as N₂, O₂, P₄, and S₈ are nonpolar. All atoms in such molecules belong to the same element. All of their bonds are nonpolar. As a result, the molecules are nonpolar.

Molecules such as CO₂ and CCl₄ are polyatomic. Besides, their atoms belong to more than one element. As a result, some of their bonds are polar. Those polar bonds will create dipoles. However, both CO₂ and CCl₄ are symmetric.  Dipoles balance within the molecule. For example, CO₂ is linear. Dipoles from the two polar C=O bonds will line up in opposite directions. They would balance each other, such that the net dipole of the CO₂ molecule is zero. As a result, CO₂ will be a nonpolar polyatomic molecule.

Similarly, C-Cl bonds in CCl₄ are polar. However, CCl₄ molecules are tetrahedral. They are symmetric. Dipoles from C-Cl bonds will add up in all four directions to produce a net dipole of zero. As a result, CCl₄ molecules are nonpolar.

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____Cl2+____H2=____HCl
Genrish500 [490]

Answer:

<u>   </u>H2 + <u>2</u><u> </u> Cl2 = <u>2</u><u> </u> HCl2

6 0
2 years ago
Adding 5.25 g of to 130 g of water in a coffee-cup calorimeter (with stirring to dissolve the salt) resulted in a decrease in te
xxTIMURxx [149]

Answer:

ΔHrxn =  - 1534.3 J

Explanation:

Given the assumptions and the formula for the change in enthalpy:

ΔHrxn = m x C x ΔT,  where

               m is the mass of solution given 135.4 g

               C is the heat capacity 4.2 J/g .K  and,

               ΔT is the change in temperature

we have ,

T₁ = ( 18.1 + 273) K = 291.1 K

T₂ = ( 15.4 +273) K = 288.4 K

ΔHrxn =  135.3 g x 4.2 J/gK x ( 288.4 -291.1 ) K = - 1534.3 J

After verifying our result has the correct unit, the answer is -1534.3 Joules, and the negative sign tells us it is an endothermic reaction decreasing the final temperature.

4 0
3 years ago
Find the volume of an object that has a mass of 20g and density of 184 glcm
expeople1 [14]
Volume= Mass/ Density= 20/184
= 0.108 cubic cm
8 0
3 years ago
Draw a structural formula for the alkene you would use to prepare the alcohol shown by hydroboration/oxidation.
Nastasia [14]

Answer:

See explanation

Explanation:

The question is incomplete because the image of the alcohol is missing. However, I will try give you a general picture of the reaction known as hydroboration of alkenes.

This reaction occurs in two steps. In the first step, -BH2 and H add to the same face of the double bond (syn addition).

In the second step, alkaline hydrogen peroxide is added and the alcohol is formed.

Note that the BH2 and H adds to the two atoms of the double bond. The final product of the reaction appears as if water was added to the original alkene following an anti-Markovnikov mechanism.

Steric hindrance is known to play a major role in this reaction as good yield of the anti-Markovnikov like product is obtained with alkenes having one of the carbon atoms of the double bond significantly hindered.

5 0
3 years ago
A chemist has to prepare 250.0 mL of a 0.300 M Na2SO4(aq) solution. What mass, in grams, of sodium sulfate (formula mass 142.05
Sedbober [7]

The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g

<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
  • Volume = 250 mL = 250 / 1000 = 0.25 L
  • Molarity = 0.3 M
  • Mole of Na₂SO₄ =?

Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.25

Mole of Na₂SO₄ = 0.075 mole

<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
  • Molar mass of Na₂SO₄ = 142.05 g/mol
  • Mole of Na₂SO₄ = 0.075 mole
  • Mass of Na₂SO₄ =?

Mass = mole × molar mass

Mass of Na₂SO₄ = 0.075 × 142.05

Mass of Na₂SO₄ = 10.65 g

Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.

Learn more about molarity:

brainly.com/question/15370276

6 0
2 years ago
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