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DochEvi [55]
2 years ago
13

What conditions must exist for a polyatomic molecule to be nonpolar?

Chemistry
1 answer:
ollegr [7]2 years ago
7 0
  • All atoms in that molecule shall belong to the same element.
  • Otherwise, dipoles must balance each other within the molecule. In such cases, the molecule needs to be symmetric.
<h3>Explanation</h3>

The molecule in question is polyatomic. It contains more than one atoms. That's a rather general definition. Among all non-metals, only the noble gases could form stable monatomic molecules.

Molecules such as N₂, O₂, P₄, and S₈ are nonpolar. All atoms in such molecules belong to the same element. All of their bonds are nonpolar. As a result, the molecules are nonpolar.

Molecules such as CO₂ and CCl₄ are polyatomic. Besides, their atoms belong to more than one element. As a result, some of their bonds are polar. Those polar bonds will create dipoles. However, both CO₂ and CCl₄ are symmetric.  Dipoles balance within the molecule. For example, CO₂ is linear. Dipoles from the two polar C=O bonds will line up in opposite directions. They would balance each other, such that the net dipole of the CO₂ molecule is zero. As a result, CO₂ will be a nonpolar polyatomic molecule.

Similarly, C-Cl bonds in CCl₄ are polar. However, CCl₄ molecules are tetrahedral. They are symmetric. Dipoles from C-Cl bonds will add up in all four directions to produce a net dipole of zero. As a result, CCl₄ molecules are nonpolar.

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5 0
3 years ago
A copper cylinder, 12.0 cm in radius, is 44.0 cm long. If the density of commoner is 8.90 g/cm3, calculate the mass in grams of
inna [77]

The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

Height of the copper cylinder H=44cm

Density of the cylinder=8.90 \frac{g}{c m^{3}}

To find:

Mass of the copper cylinder

<u>Step by Step by explanation:</u>

Solution:

According to the formula, Mass can be calculated as

\rho=\frac{m}{v} and from this

m=\rho \times v

Where, m=mass of the cylinder

\rho =density of the cylinder

v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

v=\pi r^{2} h

Where \pi=3.14

r=radius of the cylinder=12cm

h=height of the cylinder=44cm

Thus, v=3.14 \times 12^{2} \times 44

v=3.14 \times 144 \times 44

v=19895.04 \mathrm{cm}^{3}

And we know that, m=\rho \times v

Substitute the known values in the above equation we get

m=8.90 \times 19895.04  

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

4 0
3 years ago
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6 0
3 years ago
Read 2 more answers
scandium47 has a half-life of 35s. suppose you have a 45g sample of scadium 47 how much of the sample remains unchanged after 14
Mars2501 [29]

 The much  of the sample that would remain  unchanged  after 140 seconds is 2.813 g

Explanation

Half life  is time taken for the quantity  to reduce  to half its original value.

if the half life  for Scandium  is 35 sec, then the number  of half life in 140 seconds

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therefore 2.813 g  of Scandium 47 remains  unchanged.

4 0
2 years ago
How many sulfur atoms are there in 3.90 mol of sulfur?
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</span>
6 0
3 years ago
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